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R 带条件和重置的累积总和

转载 作者:行者123 更新时间:2023-12-04 23:13:47 26 4
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我有一个由 -1s 和 1s 组成的信号位置指示器向量。另外,我有一些体积数据,我想根据 Signal 的值对其进行求和。基本数据表如下所示:

df <- cbind(Signal, Volume)
head(df, 20)

Signal Volume
2016-01-04 NA 37912403
2016-01-05 -1 23258238
2016-01-06 -1 25096183
2016-01-07 -1 45172906
2016-01-08 -1 35402298
2016-01-11 -1 29932385
2016-01-12 -1 28395390
2016-01-13 -1 33410553
2016-01-14 -1 48658623
2016-01-15 1 46132781
2016-01-19 1 30998256
2016-01-20 -1 59051429
2016-01-21 1 30518939
2016-01-22 1 30495387
2016-01-25 1 32482015
2016-01-26 -1 26877080
2016-01-27 -1 58699359
2016-01-28 1 107475327
2016-01-29 1 62739548
2016-02-01 1 46132726

我想要实现的是(不使用 for 循环)是生成一个 cum Volume 向量,每次信号更改时都会重置该向量。此外,音量值应乘以信号值,即当信号为 -1 时,应将 -Volume 添加到当前 cum Volume。
基于 SO 上的类似问题,我尝试过
ave(df$a, cumsum(c(F, diff(sign(diff(df$a))) != 0)*df$Volume), FUN=seq_along) 

产生正确的信号分组,但由于某种原因不包括音量。如果没有重置,解决方案非常简单(发布在 SO 上)
require(data.table)
DT <- data.table(dt)
DT[, Cum.Sum := cumsum(Volume), by=Signal]

有谁知道用于重置和调节总和的 dplyr 或 data.table 类型的解决方案?谢谢。

最佳答案

这可以通过以下方式实现:

library(tidyverse)
library(data.table)

z %>%
group_by(rleid(Signal)) %>% #advance value every time Signal changes and group by that
mutate(cum = Signal*cumsum(Volume)) %>% #cumsum in each group
ungroup() %>% #ungroup so you could remove the grouping column
select(-4) #remove grouping column

或没有 data.table通过使用 rle :
z %>%
mutate(rl = rep(1:length(rle(Signal)$length), times = rle(Signal)$length)) %>%
group_by(rl) %>%
mutate(cum = Signal*cumsum(Volume)) %>%
ungroup() %>%
select(-4)

#output
date Signal Volume cum

<fct> <int> <int> <int>
1 2016-01-04 NA 37912403 NA
2 2016-01-05 - 1 23258238 - 23258238
3 2016-01-06 - 1 25096183 - 48354421
4 2016-01-07 - 1 45172906 - 93527327
5 2016-01-08 - 1 35402298 -128929625
6 2016-01-11 - 1 29932385 -158862010
7 2016-01-12 - 1 28395390 -187257400
8 2016-01-13 - 1 33410553 -220667953
9 2016-01-14 - 1 48658623 -269326576
10 2016-01-15 1 46132781 46132781
11 2016-01-19 1 30998256 77131037
12 2016-01-20 - 1 59051429 - 59051429
13 2016-01-21 1 30518939 30518939
14 2016-01-22 1 30495387 61014326
15 2016-01-25 1 32482015 93496341
16 2016-01-26 - 1 26877080 - 26877080
17 2016-01-27 - 1 58699359 - 85576439
18 2016-01-28 1 107475327 107475327
19 2016-01-29 1 62739548 170214875
20 2016-02-01 1 46132726 216347601

数据:
z <- read.table(text =      "date     Signal    Volume
2016-01-04 NA 37912403
2016-01-05 -1 23258238
2016-01-06 -1 25096183
2016-01-07 -1 45172906
2016-01-08 -1 35402298
2016-01-11 -1 29932385
2016-01-12 -1 28395390
2016-01-13 -1 33410553
2016-01-14 -1 48658623
2016-01-15 1 46132781
2016-01-19 1 30998256
2016-01-20 -1 59051429
2016-01-21 1 30518939
2016-01-22 1 30495387
2016-01-25 1 32482015
2016-01-26 -1 26877080
2016-01-27 -1 58699359
2016-01-28 1 107475327
2016-01-29 1 62739548
2016-02-01 1 46132726", header = T)

关于R 带条件和重置的累积总和,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49050891/

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