node.js - fulent-ffmpeg 参数输入无效 | Node

Question

我将如何编写此命令ffmpeg -i input.mov -preset slow -codec:a libfdk_aac -b:a 128k -codec:v libx264 -pix_fmt yuv420p -b:v 2500k -minrate 1500k -maxrate 4000k -bufsize 5000k -vf scale=-1:720 output.mp4作为 Node 流利的ffmpeg命令？
我有什么

function convert(input, output, callback) {
  ffmpeg(input)
    .output(output)
    .outputOptions(
      "-preset","slow","-codec:a","libfdk_aac","-b:a","128k","-codec:v","-pix_fmt","-b:v","2500k","-vf","scale","\"-1:720\""
    )
    .on("end", function () {
      console.log("conversion ended");
      callback(null);
    })
    .on("error", function (err) {
      console.log("error x: ", err);
      callback(err);
    })
    .run();
}

我收到错误说参数无效。例如但不限于:

Error: ffmpeg exited with code 1: "-1:720": Invalid argument

和其他变体

Answer 1

试试这个:

.outputOptions([
    "-preset slow",
    "-codec:a libfdk_aac",
    "-b:a 128k",
    "-codec:v libx264",
    "-pix_fmt yuv420p",
    "-b:v 2500k",
    "-vf scale=-1:720"
])

了解如何使用 outputOptions带参数 here这里是一个例子 how to scale