visual-studio - BuildingInsideVisualStudio 属性值不适用于文件引用和项目引用条件

Question

我正在尝试使用 BuildingInVsideisualStudio 属性在 csproj 中添加对相同 dll 的项目和文件引用。但是当它们一起在 csproj 中时，只会拾取文件引用。如果我删除文件引用，它会选择 csproj。我试过交换订单，但没有运气。任何想法为什么这不起作用？

这是基本思想:

<ItemGroup Condition="'$(BuildingInsideVisualStudio)' == false">
    <Reference Include="MyNamespace.Mine">
        <HintPath>..\$(OutDir)\MyNamespace.Mine.dll</HintPath>
    </Reference>
</ItemGroup>
<ItemGroup Condition="'$(BuildingInsideVisualStudio)' == '' Or '$(BuildingInsideVisualStudio)' == true">
    <ProjectReference Include="..\MyNamespace.Mine.csproj">
        <Project>{GUID}</Project>
        <Name>MyNamespace.Mine</Name>
    </ProjectReference>
</ItemGroup>

Someone else也走上了这条路，但似乎有 some caveats .由于我的构建过程无法更改，因此我需要有条件地执行此操作。使用文件引用迫使我丢失转到定义和查找所有引用(抱歉，我也无法安装 ReSharper 来解决这个问题)。

Answer 1

我看到两个问题:

你没有考虑到$(BuildingInsideVisualStudio)可以为空( '' )。对于第一个条件使用:
<ItemGroup Condition="'$(BuildingInsideVisualStudio)' != 'true'">

始终用单引号将两个操作数括起来:
<ItemGroup Condition="'$(BuildingInsideVisualStudio)' == 'true'">

MSDN reference:

Single quotes are not required for simple alphanumeric strings or boolean values. However, single quotes are required for empty values.

更新:

可能是一个长镜头，但您可以尝试在属性定义上使用条件:

<PropertyGroup Condition="'$(BuildingInsideVisualStudio)' != 'true'"><!-- In CMD -->
    <ReferenceInclude>MyNamespace.Mine"</ReferenceInclude>
    <ReferenceIncludePath>..\$(OutDir)\MyNamespace.Mine.dll</ReferenceIncludePath>
</PropertyGroup>
<PropertyGroup Condition="'$(BuildingInsideVisualStudio)' == 'true'"><!-- In VS -->
    <ProjectReferenceInclude>..\MyNamespace.Mine.csproj</ProjectReferenceInclude>
    <ProjectReferenceIncludeId>{GUID}</ProjectReferenceIncludeId>
</PropertyGroup> 

因此，引用将有条件地解析:

<ItemGroup>
    <Reference Include="$(ReferenceInclude)">
        <HintPath>$(ReferenceIncludePath)</HintPath>
    </Reference>
</ItemGroup>
<ItemGroup>
    <ProjectReference Include="$(ProjectReferenceInclude)">
        <Project>$(ProjectReferenceIncludeId)</Project>
        <Name>%(ProjectReferenceInclude.MSBuildProjectName)</Name>
    </ProjectReference>
</ItemGroup>