lua - 如何从表成员引用lua表成员？

Question

我在卢阿有一张 table :

enUS = {
   LOCALE_STHOUSANDS = ",",  --Thousands separator e.g. comma

   patNumber = "%d+["..LOCALE_STHOUSANDS.."%d]*", --regex to find a number

   ["PreScanPatterns"] = {
      ["^("..patNumber..") Armor$"] = "ARMOR",
   }
}

因此，您会看到此表中有完整的自我引用链:

LOCAL_STHOUSANDS

patNumber

["^("..patNumber..") Armor$"]

如何在lua表中执行自引用？

我不想做的就是必须替换这些值。有数百种引用文献:

enUS = {
   LOCALE_STHOUSANDS = ",",  --Thousands separator e.g. comma

   patNumber = "%d+[,%d]*", --regex to find a number

   ["PreScanPatterns"] = {
      ["^(%d+[,%d]*) Armor$"] = "ARMOR",
   }
}

Answer 1

How can i perform self-referencing in an lua table?

你不知道

Lua不是C。在构造表之前，不存在任何表项。因为表本身还不存在。因此，表构造函数中不能有一个条目引用表中不存在的另一个条目。

如果要减少重复输入，则应使用局部变量和 do/end块:

do
  local temp_thousands_separator = ","
  local temp_number_pattern = "%d+["..LOCALE_STHOUSANDS.."%d]*"

  enUS = {
   LOCALE_STHOUSANDS = temp_thousands_separator,  --Thousands separator e.g. comma

   patNumber = "%d+["..temp_thousands_separator.."%d]*", --regex to find a number

   ["PreScanPatterns"] = {
      ["^("..temp_number_pattern..") Armor$"] = "ARMOR",
   }
  }
end

do/end块在那里，因此临时变量在表创建代码之外不存在。

另外，您可以分阶段进行构建:

  enUS = {}
  enUS.LOCALE_STHOUSANDS = ",",  --Thousands separator e.g. comma

  enUS.patNumber = "%d+["..enUS.LOCALE_STHOUSANDS.."%d]*", --regex to find a number

  enUS["PreScanPatterns"] = {
      ["^("..enUS.patNumber..") Armor$"] = "ARMOR",
   }