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python - 通过管道将 OpenCV 和 PyAudio 从 python 传输到 ffmpeg 流 youtube rtmp

转载 作者:行者123 更新时间:2023-12-04 23:01:25 30 4
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如何通过管道将 openCV 和 PyAudio 传输到来自 python 的 ffmpeg 流 youtube rtmp。
错误信息显示如下:
没有这样的过滤器:“管道:1”
管道:1:无效参数
这是我的代码:
导入模块

import cv2
import subprocess
import pyaudio
声音的
p = pyaudio.PyAudio()
info = p.get_host_api_info_by_index(0)
numdevices = info.get('deviceCount')
for i in range(0, numdevices):
if (p.get_device_info_by_host_api_device_index(0, i).get('maxInputChannels')) > 0:
print("Input Device id ", i, " - ", p.get_device_info_by_host_api_device_index(0, i).get('name'))

CHUNK = 1024
FORMAT = pyaudio.paInt16
CHANNELS = 2
RATE = 44100

stream = p.open(format=FORMAT,
channels=CHANNELS,
rate=RATE,
input=True,
frames_per_buffer=CHUNK)

# Stream Audio data here
# data = stream.read(CHUNK)
视频
rtmp = r'rtmp://a.rtmp.youtube.com/live2/key'

cap = cv2.VideoCapture(0)
width = int(cap.get(cv2.CAP_PROP_FRAME_WIDTH))
height = int(cap.get(cv2.CAP_PROP_FRAME_HEIGHT))
fps = 30

命令参数在这里
command = ['ffmpeg',
'-y',
'-f', 'rawvideo',
'-pixel_format', 'bgr24',
'-video_size', "{}x{}".format(width, height),
'-framerate', str(fps),
'-i', 'pipe:0',
'-re',
'-f', 'lavfi',
'-i', 'pipe:1',
'-c:v', 'libx264',
'-c:a', 'aac',
'-vf', 'format=yuv420p',
'-f', 'flv',
rtmp]
为 ffmpeg 命令创建子进程
pipe = subprocess.Popen(command, shell=False, stdin=subprocess.PIPE
)
while cap.isOpened():
success, frame = cap.read()
if success:
if cv2.waitKey(1) & 0xFF == ord('q'):
break
pipe.stdin.write(frame.tostring())
pipe.stdin.write(stream.read(CHUNK))
音频停止
stream.stop_stream()
stream.close()
p.terminate()
视频停止
cap.release()
pipe.terminate()
谢谢

最佳答案

我已经成功地使用 CreateNamePipe 来创建视频并使用 stdin 来创建音频。

PIPE_NAME = r'\\.\pipe\VideoPipe'

video_pipe = win32pipe.CreateNamedPipe(
PIPE_NAME,
win32pipe.PIPE_ACCESS_OUTBOUND,
win32pipe.PIPE_TYPE_BYTE | win32pipe.PIPE_READMODE_BYTE | win32pipe.PIPE_WAIT,
1, 65536, 65536,
0,
None)

关于python - 通过管道将 OpenCV 和 PyAudio 从 python 传输到 ffmpeg 流 youtube rtmp,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/68527762/

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