java - 通过流将 map 列表转换为单个 map

Question

我在数据库中查询两列，其中第一列是第二列的键。
如何将结果列表转换为单个 map ？
甚至有可能吗？我刚刚看到了 bean 类的例子。

List<Map<String, Object>> steps = jdbcTemplate.queryForList(
        "SELECT key, value FROM table");

// well this doesn't work
Map<String, String> result = steps.stream()
        .collect(Collectors.toMap(s -> s.get("key"), s -> s.get("value")));

Answer 1

您忘记将键和值映射转换为生成 String :

final Map<String, String> result = steps
                .stream()
                .collect(Collectors.toMap(s -> (String) s.get("key"),
                                          s -> (String) s.get("value")));

完整示例

public static void main(String[] args) {
    final List<Map<String, Object>> steps = queryForList("SELECT key, value FROM table");
    final Map<String, String> result = steps
            .stream()
            .collect(Collectors.toMap(s -> (String) s.get("key"), s -> (String) s.get("value")));
    result.entrySet().forEach(e -> System.out.println(e.getKey() + " -> " + e.getValue()));
}

private static List<Map<String, Object>> queryForList(String s) {
    final List<Map<String, Object>> result = new ArrayList<>();

    for (int i = 0; i < 10; i++) {
        final Map<String, Object> map = new HashMap<>();
        map.put("key", "key" + i);
        map.put("value", "value" + i);
        result.add(map);
    }

    return result;
}

哪个打印

key1 -> value1
key2 -> value2
key0 -> value0
key5 -> value5
key6 -> value6
key3 -> value3
key4 -> value4
key9 -> value9
key7 -> value7
key8 -> value8