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Django:动态 success_url 导致 "' NoneType' 对象没有属性 'find'"

转载 作者:行者123 更新时间:2023-12-04 22:47:54 26 4
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我想重定向 success_url表格提交并生效后到同一个表格。 Online我找到了一个解决方案的描述,但是这个解决方案和我的其他代码选项生成了相同的错误消息。

Exception Value: 'NoneType' object has no attribute 'find'

网址.py
url(r'^pictures/(?P<id>\d+)/$', PictureUpload.as_view(), name='picture_upload'),
...

第一个 views.py 选项

复制现有的链接路径
class PictureUpload(FormView):
form_class = PictureForm
template_name = 'picture_upload.html'
def get_success_url(self):
success_url = lambda self: self.request.path

第二个 views.py 选项

根据反向 url 加上 id 重新创建链接路径
class PictureUpload(FormView):
form_class = PictureForm
template_name = 'picture_upload.html'
def get_success_url(self):
success_url = reverse('picture_upload',
kwargs={'id': self.kwargs.get('id', None)})

这两个选项都以相同的回溯结束。
Request Method: POST
Request URL: http://127.0.0.1:8000/pictures/2/

Django Version: 1.5.1
Python Version: 2.7.1
Installed Applications:
('django.contrib.admin',
'django.contrib.admindocs',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.gis',
'django.contrib.humanize',
'django.contrib.sessions',
'django.contrib.sites',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.admin',
'django.contrib.admindocs',
'picture',
'debug_toolbar')
Installed Middleware:
('django.middleware.common.CommonMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'debug_toolbar.middleware.DebugToolbarMiddleware')


Traceback:
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/core/handlers/base.py" in get_response
115. response = callback(request, *callback_args, **callback_kwargs)
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/views/generic/base.py" in view
68. return self.dispatch(request, *args, **kwargs)
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/views/generic/base.py" in dispatch
86. return handler(request, *args, **kwargs)
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/views/generic/edit.py" in post
165. return self.form_valid(form)
File "/Users/Development/project/apps/picture/picture_views.py" in form_valid
180. return super(PictureUpload, self).form_valid(form)
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/views/generic/edit.py" in form_valid
65. return HttpResponseRedirect(self.get_success_url())
File "/Users/Development/virtual-re/lib/python2.7/site-packages/django/http/response.py" in __init__
388. parsed = urlparse(redirect_to)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urlparse.py" in urlparse
134. tuple = urlsplit(url, scheme, allow_fragments)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urlparse.py" in urlsplit
173. i = url.find(':')

Exception Type: AttributeError at /pictures/2/
Exception Value: 'NoneType' object has no attribute 'find'

最佳答案

看起来你的 get_success_url 都不是实现实际上返回 URL,因此假设这不仅仅是一个剪切和粘贴错误,您将 None 传递给 HttpResponseRedirect。

关于Django:动态 success_url 导致 "' NoneType' 对象没有属性 'find'",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16489944/

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