playframework - 如何将 Play 的 "dist"zip 文件发布到远程 Maven 存储库？

Question

我在将 Play 的应用程序分发 zip 文件发布到远程 maven 存储库时遇到问题。

有很多关于这方面的帖子和博客，但似乎没有什么对我有用。它们要么不完整，要么过时。

例如，这里有一段摘录:

val distHack = TaskKey[sbt.File]("dist-hack", "Hack to publish dist")

val myDistSettings = Seq[Setting[_]] (
  publish <<= (publish) dependsOn play.Project.dist,
  publishLocal <<= (publishLocal) dependsOn play.Project.dist,
  artifact in distHack ~= { (art: Artifact) =>
    art.copy(`type` = "zip", extension = "zip")
  },
  distHack <<= (distDirectory, version) map { (d, v) =>
    val packageName = "%s-%s" format(projectName, v)
    val zip = d / (packageName + ".zip")
    zip
  }
) ++ Seq(addArtifact(artifact in distHack, distHack).settings: _*)

play.Project.dist 在最新版本的 play 中不再是对“dist”的有效引用。

另外，如何正确指定“distDirectory”以及从何处获取“projectName”？

此外，大多数示例都旨在将代码包含在构建的 .scala 文件中。我试图变得简单并在我的构建的 .sbt 文件中指定它。

如果这种方法适用于任何人，您能否发布一个完整的示例？

谢谢!

Answer 1

我在 build.sbt 中使用此配置将 zip 文件发布到远程 maven 存储库。

lazy val dist = com.typesafe.sbt.SbtNativePackager.NativePackagerKeys.dist

publish <<= (publish) dependsOn  dist

publishLocal <<= (publishLocal) dependsOn dist

val distHack = TaskKey[File]("dist-hack", "Hack to publish dist")

artifact in distHack ~= { (art: Artifact) => art.copy(`type` = "zip", extension = "zip") }

val distHackSettings = Seq[Setting[_]] (
  distHack <<= (target in Universal, normalizedName, version) map { (targetDir, id, version) =>
    val packageName = "%s-%s" format(id, version)
    targetDir / (packageName + ".zip")
  }) ++ Seq(addArtifact(artifact in distHack, distHack).settings: _*)

seq(distHackSettings: _*)

如果您只想发布 zip 文件，而不是其他人工制品，请将其添加到 build.sbt:

publishArtifact in (Compile, packageBin) := false

publishArtifact in (Compile, packageDoc) := false

publishArtifact in (Compile, packageSrc) := false

使用 sbt publish将 zip 发送到远程仓库。当您使用 sbt-release 时，它也像魅力一样工作.