sql - SOLR DataImportHandler，如何将嵌套实体视为 JSON 数组

Question

我正在为 SOLR 和 SQL 数据导入而苦恼。我需要索引来自 2 个表的数据，第一个是“masters”，第二个是“details”。这两个表之间的关系是 1 对 n 的，它由两个表上的列 m_id 强制执行:

CREATE TABLE "masters" (m_id             NUMBER(10), 
                        m_code           VARCHAR2(100 CHAR), 
                        m_description    VARCHAR2(1000 CHAR),
                        PRIMARY KEY (m_id));

CREATE TABLE "details" (d_id             NUMBER(10), 
                        s_code           VARCHAR2(100 CHAR), 
                        s_description    VARCHAR2(1000 CHAR), 
                        m_id             NUMBER(10), 
                        PRIMARY KEY (d_id),
                        CONSTRAINT fk_details_masters FOREIGN KEY (m_id) REFERENCES "masters"(m_id));

我想为“masters”表中的每一行创建一个索引文档，每个文档都应包含“details”表的数组。

我在脑海中预想的结果是这样的:

master = {
 "ID": "1"
 "m_code": "master53",
 "m_description": "John Doe",
 "details": [ 
              {
               "d_code": "detail001",
               "d_description": "Shirts"
              },
              {
               "d_code": "detail002",
               "d_description": "Shoes"
              },
              {
               "d_code": "detail003",
               "d_description": "hats"
              }
            ]
}

但我只能产生这样的东西:

master = {
 "ID": "1",
 "m_code": "master53",
 "m_description": "John Doe",
 "d_code": ["detail001","detail002","detail003"],
 "d_description": ["Shirts","Shoes","hats"]
}

使用这样的配置:

<dataConfig>
  <dataSource type="JdbcDataSource" 
              driver="oracle.jdbc.driver.OracleDriver"
              url="jdbc:oracle:thin:@//dora64svil.icc.crifnet.com:1521/cbrisvil.dbcrif.net"
              user="CBBTC" 
              password="w4.gJ6Qf1p7Z_i4qFp3W_d"/>
  <document>
    <entity name="master" rootEntity="True"
            query="SELECT m_id, m_code, m_description from master">
        <field column="m_id" name="ID"/>
        <field column="m_code" name="m_code_s"/>
        <field column="m_description" name="m_description_s"/>
        <entity name="details"  rootEntity="False"
                query="SELECT d_code, d_description from details where = m_id '${master.m_id}'">
            <field column="d_code" name="d_code_ss"/>
            <field column="d_description" name="d_description_ss"/>
        </entity>
    </entity>
  </document>
</dataConfig>

我在配置和 schema.xml 字段定义方面玩了很多，但我无法找到正确的方法。(字段后缀“_s”和“_ss”的存在只是为了将正确的字段类型触发到模式中)

我想我正在尝试做的是给嵌套实体一个“名字”，错误在哪里？我试图做的事情在概念上是错误的吗？

Answer 1

您必须在 schema.xml 中将字段设置为 multiValued=true