Java 异常之间的持续时间

Question

我使用 java Duration between 方法来计算 LocalTime 和 LocalDateTime 之间的持续时间，当我将 localTime 作为方法的第一个参数时它可以工作，但是当我颠倒顺序时，它给出了异常 DateTimeException :

这项工作很好:

 LocalTime t1 = LocalTime.now();
 LocalDateTime t2 = LocalDateTime.now();
 System.out.println(Duration.between(t1, t2));

当我反转 agrs 时，它给了我一个异常(exception):

 LocalTime t1 = LocalTime.now();
 LocalDateTime t2 = LocalDateTime.now();
 System.out.println(Duration.between(t2, t1));

Exception in thread "main" java.time.DateTimeException: Unable to obtain LocalDateTime from TemporalAccessor: 16:32:18.553 of type java.time.LocalTime

有人可以解释为什么我得到这个异常感谢任何帮助:=)

Answer 1

来自文档:Duration between

If the objects are of different types, then the duration is calculated based on the type of the first object. For example, if the first argument is a LocalTime then the second argument is converted to a LocalTime.

所以基本上，抛出错误是因为你不能将 LocalTime 对象转换为 LocalDateTime，日期信息不包含在 LocalTime 中。