php - 试图用单引号括起一个 php 变量

Question

我试图在 PHP 中将一个 variable 括在单引号中。这是我的代码:

$my_post = array(
            'post_title' => $orderRequestCode.' - ' . $customerName,
            'post_content' => $orderContent,
            'post_status' => 'draft',
            'post_author' => "'".$user_ID."'",
            'post_type' => 'orders'
            );

当前 var_dump($my_post) 输出:

array (size=5)
  'post_title' => string '2014-06-13-15-13-52 - xxxxxxx' (length=35)
  'post_content' => string 'Order Code: 2014-06-13-15-13-52
   Customer Name: xxxxxxxxxxxx
   Customer Email: xxx@xxxx.xx
   Order Items: 
   Stock Code: Q20-50-6101 Quantity: 12
   Comments: 
' (length=162)
  'post_status' => string 'draft' (length=5)
  'post_author' => string ''1'' (length=3)     <--------------- should be '1'
  'post_type' => string 'orders' (length=6)

这一行:

'post_author' => string ''1'' (length=3)

需要:

'post_author' => string '1' (length=3)

Answer 1

var_dump 中的外部引号实际上并不是字符串的一部分，因此长度是 3，而不是 5。如果你回显你的字符串，它将是 '1'