json - 正确解析 JSON 响应文本

Question

我正在创建的 Excel 程序中有问题。简而言之，我必须从网站中提取 JSON 数据，对其进行解析，然后将响应扔到工作表中以供以后使用。每当代码到达要输出响应文本的位置时，输出就会从响应文本中传递我需要的第一组数据。以下所有数据和示例。

创建和发送 HTTP 请求的代码:

For i = 1 To 100
    URL = "REDACTED"

Set httpRequest = CreateObject("MSXML2.XMLHTTP")
httpRequest.Open "GET", URL, False
httpRequest.setRequestHeader "Content-Type", "application/x-www-form-urlencoded"
httpRequest.send ""

Set Output = parse(httpRequest.responseText)

Pallet_Inv.Cells(1 + i, d) = Output.Item("result").Item("contains").Item(i).Item("resourceLabel")

Next

Pallet_Inv 是响应文本需要输出到的工作表。
“(1 + i，d)”在那里，因为我在工作表上有一个标题，输出将转到我不想被覆盖的地方。

解析从请求返回的响应文本的代码:

Public Function parse(ByRef str As String) As Object

   Dim Index As Long
   Index = 1
   psErrors = ""
   On Error Resume Next
   Call skipChar(str, Index)
   Select Case Mid(str, Index, 1)
      Case "{"
         Set parse = parseObject(str, Index)
      Case "["
         Set parse = parseArray(str, Index)
      Case Else
         psErrors = "Invalid JSON"
   End Select


End Function
'   skip special character
'
Private Sub skipChar(ByRef str As String, ByRef Index As Long)
   Dim bComment As Boolean
   Dim bStartComment As Boolean
   Dim bLongComment As Boolean
   Do While Index > 0 And Index <= Len(str)
      Select Case Mid(str, Index, 1)
      Case vbCr, vbLf
         If Not bLongComment Then
            bStartComment = False
            bComment = False
         End If

      Case vbTab, " ", "(", ")"

      Case "/"
         If Not bLongComment Then
            If bStartComment Then
               bStartComment = False
               bComment = True
            Else
               bStartComment = True
               bComment = False
               bLongComment = False
            End If
         Else
            If bStartComment Then
               bLongComment = False
               bStartComment = False
               bComment = False
            End If
         End If

      Case "*"
         If bStartComment Then
            bStartComment = False
            bComment = True
            bLongComment = True
         Else
            bStartComment = True
         End If

      Case Else
         If Not bComment Then
            Exit Do
         End If
      End Select

      Index = Index + 1
   Loop

 End Sub
 '
 '   parse collection of key/value
 '
Private Function parseObject(ByRef str As String, ByRef Index As Long) As Dictionary

   Set parseObject = New Dictionary
   Dim sKey As String

   ' "{"
   Call skipChar(str, Index)
   If Mid(str, Index, 1) <> "{" Then
      psErrors = psErrors & "Invalid Object at position " & Index & " : " & Mid(str, Index) & vbCrLf
      Exit Function
   End If

   Index = Index + 1

   Do
      Call skipChar(str, Index)
      If "}" = Mid(str, Index, 1) Then
         Index = Index + 1
         Exit Do
      ElseIf "," = Mid(str, Index, 1) Then
         Index = Index + 1
         Call skipChar(str, Index)
      ElseIf Index > Len(str) Then
         psErrors = psErrors & "Missing '}': " & Right(str, 20) & vbCrLf
         Exit Do
      End If


      ' add key/value pair
      sKey = parseKey(str, Index)
      On Error Resume Next

      parseObject.Add sKey, parseValue(str, Index)
      If Err.Number <> 0 Then
         psErrors = psErrors & Err.Description & ": " & sKey & vbCrLf
         Exit Do
      End If
   Loop
eh:

End Function

Private Function parseKey(ByRef str As String, ByRef Index As Long) As String

   Dim dquote  As Boolean
   Dim squote  As Boolean
   Dim Char    As String

   Call skipChar(str, Index)
   Do While Index > 0 And Index <= Len(str)
      Char = Mid(str, Index, 1)
      Select Case (Char)
         Case """"
            dquote = Not dquote
            Index = Index + 1
            If Not dquote Then
               Call skipChar(str, Index)
               If Mid(str, Index, 1) <> ":" Then
                  psErrors = psErrors & "Invalid Key at position " & Index & " : " & parseKey & vbCrLf
                  Exit Do
               End If
            End If
         Case "'"
            squote = Not squote
            Index = Index + 1
            If Not squote Then
               Call skipChar(str, Index)
               If Mid(str, Index, 1) <> ":" Then
                  psErrors = psErrors & "Invalid Key at position " & Index & " : " & parseKey & vbCrLf
                  Exit Do
               End If
            End If
         Case ":"
            Index = Index + 1
            If Not dquote And Not squote Then
               Exit Do
            Else
               parseKey = parseKey & Char
            End If
         Case Else
            If InStr(vbCrLf & vbCr & vbLf & vbTab & " ", Char) Then
            Else
               parseKey = parseKey & Char
            End If
            Index = Index + 1
      End Select
   Loop

End Function
'
'   parse string / number / object / array / true / false / null
'
Private Function parseValue(ByRef str As String, ByRef Index As Long)

   Call skipChar(str, Index)

   Select Case Mid(str, Index, 1)
      Case "{"
         Set parseValue = parseObject(str, Index)
      Case "["
         Set parseValue = parseArray(str, Index)
      Case """", "'"
         parseValue = parseString(str, Index)
      Case "t", "f"
         parseValue = parseBoolean(str, Index)
      Case "n"
         parseValue = parseNull(str, Index)
      Case Else
         parseValue = parseNumber(str, Index)
   End Select

End Function
'
'   parse list
'
Private Function parseArray(ByRef str As String, ByRef Index As Long) As Collection

   Set parseArray = New Collection

   ' "["
   Call skipChar(str, Index)
   If Mid(str, Index, 1) <> "[" Then
      psErrors = psErrors & "Invalid Array at position " & Index & " : " + Mid(str, Index, 20) & vbCrLf
      Exit Function
   End If

   Index = Index + 1

   Do

      Call skipChar(str, Index)
      If "]" = Mid(str, Index, 1) Then
         Index = Index + 1
         Exit Do
      ElseIf "," = Mid(str, Index, 1) Then
         Index = Index + 1
         Call skipChar(str, Index)
      ElseIf Index > Len(str) Then
         psErrors = psErrors & "Missing ']': " & Right(str, 20) & vbCrLf
         Exit Do
      End If

      ' add value
      On Error Resume Next
      parseArray.Add parseValue(str, Index)
      If Err.Number <> 0 Then
         psErrors = psErrors & Err.Description & ": " & Mid(str, Index, 20) & vbCrLf
         Exit Do
      End If
   Loop

End Function
'
'   parse number
'
Private Function parseNumber(ByRef str As String, ByRef Index As Long)

   Dim Value   As String
   Dim Char    As String

   Call skipChar(str, Index)
   Do While Index > 0 And Index <= Len(str)
      Char = Mid(str, Index, 1)
      If InStr("+-0123456789.eE", Char) Then
         Value = Value & Char
         Index = Index + 1
      Else
         parseNumber = CDec(Value)
         Exit Function
      End If
   Loop
End Function
'
'   parse string
'
Private Function parseString(ByRef str As String, ByRef Index As Long) As String

   Dim quote   As String
   Dim Char    As String
   Dim Code    As String

   Dim SB As New cStringBuilder

   Call skipChar(str, Index)
   quote = Mid(str, Index, 1)
   Index = Index + 1

   Do While Index > 0 And Index <= Len(str)
      Char = Mid(str, Index, 1)
      Select Case (Char)
         Case "\"
            Index = Index + 1
            Char = Mid(str, Index, 1)
            Select Case (Char)
               Case """", "\", "/", "'"
                  SB.Append Char
                  Index = Index + 1
               Case "b"
                  SB.Append vbBack
                  Index = Index + 1
               Case "f"
                  SB.Append vbFormFeed
                  Index = Index + 1
               Case "n"
                  SB.Append vbLf
                  Index = Index + 1
               Case "r"
                  SB.Append vbCr
                  Index = Index + 1
               Case "t"
                  SB.Append vbTab
                  Index = Index + 1
               Case "u"
                  Index = Index + 1
                  Code = Mid(str, Index, 4)
                  SB.Append ChrW(Val("&h" + Code))
                  Index = Index + 4
            End Select
         Case quote
            Index = Index + 1

            parseString = SB.toString
            Set SB = Nothing

            Exit Function

         Case Else
            SB.Append Char
            Index = Index + 1
      End Select
   Loop

   parseString = SB.toString
   Set SB = Nothing

End Function

来自网站的原始 JSON 数据:

{"result":{"contains":[{"cptInMillis":1547531880000,"containerType":"Case
","cpt":"REDACTED
PM","stackingFilter":"REDACTED","associationReason":"-","isEmpty":"-","resourceLabel":"csXP25jMSzG","associatedUser":"REDACTED","cleanupAllowed":false,"isClosed":"-","containerId":"REDACTED","isForcedMove":"No","dwellTime":"REDACTED
: 1"},{"cptInMillis":1547531880000,"containerType":"Case
","cpt":"REDACTED
PM","stackingFilter":"REDACTED","associationReason":"-","isEmpty":"-","resourceLabel":"csXP25jMTHk","associatedUser":"REDACTED","cleanupAllowed":false,"isClosed":"-","containerId":"REDACTED","isForcedMove":"No","dwellTime":"REDACTED
: 2"},{"cptInMillis":1547531880000,"containerType":"Case
","cpt":"REDACTED
PM","stackingFilter":"REDACTED","associationReason":"-","isEmpty":"-","resourceLabel":"csXP25jMTN5","associatedUser":"REDACTED","cleanupAllowed":false,"isClosed":"-","containerId":"REDACTED","isForcedMove":"No","dwellTime":"REDACTED
: 2"},{"cptInMillis":1547445480000,"containerType":"Case
","cpt":"REDACTED
PM","stackingFilter":"REDACTED","associationReason":"-","isEmpty":"-","resourceLabel":"csXP25k9Z5F","associatedUser":"REDACTED","cleanupAllowed":false,"isClosed":"-","containerId":"REDACTED","isForcedMove":"No","dwellTime":"REDACTED
: 2"}],"endToken":null,"startToken":"0"},"ok":true,"message":""}

现在由于一些数据是 secret 的，我已经对其进行了编辑，但是我真正需要的东西我已经保留了。

我需要在此处添加的 JSON 数据中存在的“resourceLabel”对象。

现在我确实得到了数据，但是它开始在第二个“resourceLabel”对象而不是第一个输出。

我需要的:

csXP25jMSzG  csXP25jMTHk  csXP25jMTN5  csXP25k9Z5F

我不断得到的:

csXP25jMTHk
csXP25jMTN5
csXP25k9Z5F

现在我可能只是遗漏了一些明显的东西，但我不确定为什么会这样。如果这个问题太复杂，太长，或者解释不够，请告诉我。或者，如果 Stack 不是此类问题的正确位置，请指导我去其他地方。

任何帮助，将不胜感激。
谢谢你。

Answer 1

除非您的主要目标是编写 JSON 解析器，否则我建议您使用现有的 JSON 转换器。我一直在使用 GitHub 中的那个.使用该转换器，获得resourceLabel 相对容易。 .这是一种方法:

Option Explicit
Sub pj()
    Dim strJSON As String
    Dim JSON As Dictionary
    Dim dRES As Dictionary
    Dim oContains As Collection
    Dim V

strJSON = Cells(1, 1).Value2
Set JSON = parsejson(strJSON)
Set dRES = JSON("result")
Set oContains = dRES("contains")

For Each V In oContains
    Debug.Print V("resourceLabel")
Next V

End Sub

使用 A1 中的 JSON 字符串， 输出:

csXP25jMSzG
csXP25jMTHk
csXP25jMTN5
csXP25k9Z5F