r - 填充缺失值

Question

我有一个这样的数据集

 4  6 18 12  4  5
 2  9  0  3 NA 13
11 NA  6  7  7  9

如何使用 R 填充缺失值？

Answer 1

如果你想用固定值替换你的 NAs(a 是你的数据集):

a[is.na(a)] <- 0 #For instance

如果你想用一个作为行号和列号函数的值替换它们(正如你在评论中所建议的那样):

#This will replace them by the sum of their row number and their column number:
a[is.na(a)] <- rowSums(which(is.na(a), arr.ind=TRUE))

#This will replace them by their row number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,1]

#And this by their column number:
a[is.na(a)] <- which(is.na(a), arr.ind=TRUE)[,2]