php - (laravel)使用变量名模型的查询构建器

Question

我正在尝试使用它的 laravel 模型类插入到一个表中，但我需要能够插入到一个变量指示的表中。如何才能做到这一点？我尝试了 vanilla PHP moethod 和 laravel facade 方法，但都给了我错误:

$modelName = "model";

# this works no problem:
$model = new model();

# this blows up:
$model = new $modelName();

# this blows up:
$model::create($request->all());

laravel报错:

FatalThrowableError in Controller.php line 44:
Class 'model' not found

Answer 1

您必须输入完全限定的类名:

One must use the fully qualified name (class name with namespace prefix).

$modelName = "App\\User"; // assuming User is located in the App namespace
$model = new $modelName();

你可以了解更多here .