gpt4 book ai didi

vba - 需要帮助 LOOPING 功能

转载 作者:行者123 更新时间:2023-12-04 22:06:44 25 4
gpt4 key购买 nike

我的代码有问题...看起来像这样

Worksheets("Daily Consump").Cells(67, OutputNumber).Value = (CDbl(Kiln.Cells(25, OutputNumber + 3).Value) - CDbl(Kiln.Cells(25, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(25, 4).Value)
Worksheets("Daily Consump").Cells(68, OutputNumber).Value = (CDbl(Kiln.Cells(26, OutputNumber + 3).Value) - CDbl(Kiln.Cells(26, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(26, 4).Value)
Worksheets("Daily Consump").Cells(69, OutputNumber).Value = (CDbl(Kiln.Cells(27, OutputNumber + 3).Value) - CDbl(Kiln.Cells(27, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(27, 4).Value)
Worksheets("Daily Consump").Cells(70, OutputNumber).Value = (CDbl(Kiln.Cells(28, OutputNumber + 3).Value) - CDbl(Kiln.Cells(28, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(28, 4).Value)
Worksheets("Daily Consump").Cells(71, OutputNumber).Value = (CDbl(Kiln.Cells(29, OutputNumber + 3).Value) - CDbl(Kiln.Cells(29, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(29, 4).Value)
Worksheets("Daily Consump").Cells(72, OutputNumber).Value = (CDbl(Kiln.Cells(30, OutputNumber + 3).Value) - CDbl(Kiln.Cells(30, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(30, 4).Value)
Worksheets("Daily Consump").Cells(73, OutputNumber).Value = (CDbl(Kiln.Cells(31, OutputNumber + 3).Value) - CDbl(Kiln.Cells(31, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(31, 4).Value)

我认为我的代码不好,你有什么建议用简单的代码制作它,也许使用循环,但我有任何失败:
这是我的审判
'For k = 25 To 31
' For j = 67 To 73
' Worksheets("Daily Consump").Cells(j, OutputNumber).Value = (CDbl(Kiln.Cells(k, OutputNumber + 3).Value) - CDbl(Kiln.Cells(k, OutputNumber + 2).Value)) * CDbl(Kiln.Cells(k, 4).Value)
' Next j
'Next k

请告诉我该怎么做

最佳答案

With Kiln
For k = 25 To 31
Worksheets("Daily Consump").Cells(k + 42, OutputNumber).value = (CDbl(.Cells(k, OutputNumber + 3).value) - CDbl(.Cells(k, OutputNumber + 2).value)) * CDbl(.Cells(k, 4).value)
Next k
End With

关于vba - 需要帮助 LOOPING 功能,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19801491/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com