sql - 在 SQL 查询中对月份名称进行排序

Question

我当前的查询是:

SELECT FORMAT(Date, 'MMM') as 'Date', FORMAT(Date, 'yyy') as 'Year' 
,COUNT(*) 
as 'Tickets Generated'
FROM [SambaData2].[dbo].[Tickets]
GROUP BY FORMAT(Date, 'MMM'), FORMAT(Date, 'yyy')
ORDER BY Date

它返回值:

我希望相同的查询返回带年份的排序月份名称!

Answer 1

为了提高查询效率，我会避免使用 format() 方法。

select
       left(datename(month,[Date]),3) [Month]
     , year([Date]) [Year]
     , [Tickets Generated]
from (
        SELECT
               dateadd(month,datediff(month,0,t.[Date]),0) as [Date]
             , COUNT(*) as [Tickets Generated]
        FROM [SambaData2].[dbo].[Tickets] AS t
        GROUP BY dateadd(month,datediff(month,0,t.[Date]),0)
    ) as d
ORDER BY [Date]

此方法的核心如下:

dateadd(month,datediff(month,0,t.[Date]),0)

这具有定位相关年份和月份的第一天的效果，从而为 order by 子句留下一个完整的日期，但仍然分组到所需的级别。运行 foillowing 可能有助于解释

select 
  datediff(month,0,getdate()) a
, dateadd(month,datediff(month,0,getdate()),0) b
, left(datename(month,getdate()),3) c
, getdate() d


   a          b        c              d           
 ------- ------------ ----- --------------------- 
  1425    2018-10-01   Oct   2018-10-04 08:08:19