awk 脚本 : How to prevent ARGV from being treated as an input file name

Question

似乎 awk 脚本将 ARGV[1] 到 ARGV[ARGC] 视为输入文件。

有没有办法让 awk 将 ARGV 视为简单的参数而不是输入文件

例子:

测试.awk

#!/usr/bin/awk -f
BEGIN {title=ARGV[2]}
{if ($1=="AA") {print title}}

数据文件

AB
BA
AA
CC

$ test.awk dat 'My Interesting Title'

My Interesting Title awk: test.awk:3: fatal: cannot open file `My Interesting Title' for reading (No such file or directory)

Answer 1

像这样的东西？

$ awk -v title='My Interesting Title' '$0 ~ /AA/ {print title}1' input
AB
BA
My Interesting Title
AA
CC