json - 是否可以使Scala的JSON.parseFull()不将整数视为小数？

Question

我正在使用JSON.parseFull()解析此字符串。这种方法对我来说真的很方便，因为我需要获取 map

val jStr = """{"wt":"json","rows":500}"""
println( JSON.parseFull(jStr) )

这是输出:

Some(Map(wt -> json, rows -> 500.0)) // ´rows´ as Double

我想找一个Integer而不是Double。

Some(Map(wt -> json, rows -> 500)) // ´rows´ as Integer

那可能吗？

Answer 1

从Scala's JSON documentation

The default conversion for numerics is into a double. If you wish to override this behavior at the global level, you can set the globalNumberParser property to your own (String => Any) function. If you only want to override at the per-thread level then you can set the perThreadNumberParser property to your function

在您的情况下:

val myConversionFunc = {input : String => Integer.parseInt(input)}
JSON.globalNumberParser = myConversionFunc

scala> println(JSON.parseFull(jStr))

Some(Map(wt-> json，行-> 500))