lua - 对表数组进行排序

Question

这可能比我自己做更容易。我对 Lua 比较陌生，但对其他语言有经验。

我有一张看起来像这样的表:

local state = {}
state[1] = {
   show = true,
   changed = true,
   progressType = "static",
   value = 0,
   total = 9,
   name = "nine",
}

state[2] = {
   show = true,
   changed = true,
   progressType = "static",
   value = 0,
   total = 7,
   name = "seven",
}

state[3] = {
   show = true,
   changed = true,
   progressType = "static",
   value = 0,
   total = 8,
   name = "eight",
}

state[4] = {
   show = true,
   changed = true,
   progressType = "static",
   value = 0,
   total = 6,
   name = "six",
}

我需要做的是对每个进行排序 table[]基于 table.value5 的值的条目.我在文档中找不到任何明确说它们不仅仅是基本的功能 table.sort所以我发现自己有点卡住了。我是否需要通过迭代并使用排序数据创建新表来手动排序？

Answer 1

I can't find any functions in the docs that expressely say they do more than just a basic table.sort so I find myself a bit stuck.

我可能误解了您的问题，但是 table.sort在这种情况下正是您所需要的:

local state = {}
state[1] = {
   total = 9,
   name = "nine",
}

state[2] = {
   total = 7,
   name = "seven",
}

state[3] = {
   total = 8,
   name = "eight",
}

state[4] = {
   total = 6,
   name = "six",
}

-- Use table.sort with a custom anonymous function
-- to specify how to compare the nested tables.
table.sort(state, function (a, b) 
    return a.total < b.total
end)

for i=1, #state do
  print(i, state[i].name)
end

与 table.sort您可以提供一个可选的自定义函数，它可以随您的需要简单或复杂。在这种情况下(根据您的问题)只需比较 total 就足够了。表的值。