angularjs - Angular promise 在函数内部而不是在外部解析

Question

我有一个递归函数，每半秒左右检查一些数据。该函数返回一个 promise 。找到数据后，我想解析 promise 并将数据作为解析传递。问题是，promise 不会在函数之外调用 .then() 。这是 fiddle :http://jsfiddle.net/btyg1u0g/1/ .

这是 fiddle 代码:

服务:

myApp.factory('myService', function($q, $timeout) {

    var checkStartTime = false;
    var checkTimeout = 30000;

    function checkForContent() {

        var deferred = $q.defer();

        // simulating an $http request here
        $timeout(function () {

            console.log("Checking...");

            if (!checkStartTime) checkStartTime = new Date();

            // this would normally be 'if (data)'
            if ((new Date()) - checkStartTime > 3000) {
                deferred.resolve("Finished check");
                checkStartTime = false; // reset the timeout start time
            } else {
                // if we didn't find data, wait a bit and check again
                $timeout(function () {
                    checkForContent();
                }, 400);
            }

        }, 5);

        // then is called in here when we find data
        deferred.promise.then(function(message) {
             console.log("Resolved inside checkForContent");
        });

        return deferred.promise;

    }

    return {
        runCheck: function() {
            return checkForContent()
        }
    }
});

Controller :

myApp.controller('MyCtrl', function ($scope, myService) {
    $scope.name = 'Superhero';

    // then is never called
    myService.runCheck()
    .then(function (message) {
        console.log("Resolved outside checkForContent");
    });

});

Answer 1

退房 this fiddle .

外$timeout函数被命名，所以它可以从自身内部调用。

$timeout(function inner() {
  // ...

然后像这样递归地调用它:

$timeout(function () {
  inner();
}, 400);