python - 解包值过多时出现错误(预期2)

Question

我想从我的函数返回两个不同的值如何重写我的代码以在两个不同的变量中返回这两个值。

所以我得到这个错误:

Traceback (most recent call last):
  File "features.py", line 300, in <module>
    fea1, fea2 = build_feature_matrix_S(sentences)
ValueError: too many values to unpack (expected 2)

这里的代码

def build_feature_matrix_S(documents):

    feature_type = ['frequency','tfdif']
    #feature_type = feature_type.lower().strip()

    for f in feature_type:

        if feature_type == 'frequency':
            vectorizer_freq = CountVectorizer(tokenizer = tokenize_lemmatize_spacy, binary=False, min_df=5, ngram_range=(1, 2))
            feature_matrix_freq = vectorizer_freq.fit_transform(documents)
            feature_freq = pd.DataFrame(feature_matrix_freq.todense(), columns = vectorizer_freq.get_feature_names())

            return feature_freq

        else:

            vectorizer_tfidf = TfidfVectorizer(tokenizer = tokenize_lemmatize_spacy, min_df=5, ngram_range=(1, 2))
            feature_matrix_tfidf = vectorizer_tfidf.fit_transform(documents)
            feature_tfidf = pd.DataFrame(feature_matrix_tfidf.todense(), columns = vectorizer_tfidf.get_feature_names())

            return feature_tfidf

fea1, fea2 = build_feature_matrix_S(sentences)

print(fea1, fea2)

Answer 1

在这一行中，

fea1, fea2 = build_feature_matrix_S(sentences)

python期望返回2个变量，一个元组，并且函数build_feature_matrix_S()中的两个return语句都没有这样做，返回超过2个。

    feature_freq = pd.DataFrame(feature_matrix_freq.todense(), columns = vectorizer_freq.get_feature_names())

    return feature_freq

或者

            feature_tfidf = pd.DataFrame(feature_matrix_tfidf.todense(), columns = vectorizer_tfidf.get_feature_names())

            return feature_tfidf

因此错误。