php - Guzzle 6 发送多部分数据

Question

我想向 Guzzle Http 请求添加一些数据。有文件名，文件内容和带有授权 key 的标题。

$this->request = $this->client->request('POST', 'url', [
    'multipart' => [
        'name' => 'image_file',
        'contents' => fopen('http://localhost:8000/vendor/l5-swagger/images/logo_small.png', 'r'),
        'headers' =>
            ['Authorization' => 'Bearer uCMvsgyuYm0idmedWFVUx8DXsN8QzYQj82XDkUTw']
            ]]);

但我得到错误

Catchable Fatal Error: Argument 2 passed to GuzzleHttp\Psr7\MultipartStream::addElement() must be of the type array, string given, called in vendor\guzzlehttp\psr7\src\MultipartStream.php on line 70 and defined in vendor\guzzlehttp\psr7\src\MultipartStream.php line 79

在 Guzzle 6 文档中是这样的: http://docs.guzzlephp.org/en/latest/request-options.html#multipart

谁知道我哪里出错了？

Answer 1

这是解决方案。带有访问 token 的标题应该在 multipart 部分之外。

$this->request = $this->client->request('POST', 'request_url', [
            'headers' => [
                'Authorization' => 'Bearer access_token'
            ],
            'multipart' => [
                [
                    'Content-type' => 'multipart/form-data',
                    'name' => 'image_file',
                    'contents' => fopen('image_file_url', 'r')
                ]
            ]
        ]);