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SQL 动态旋转 "Week"表

转载 作者:行者123 更新时间:2023-12-04 21:02:28 25 4
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表格设计:

| PeriodStart | Person | Day1 | Day2 | Day3 | Day4 | Day5 | Day6 | Day7 |
-------------------------------------------------------------------------
| 01/01/2018 | 123 | 2 | 4 | 6 | 8 | 10 | 12 | 14 |
| 01/15/2018 | 246 | 1 | 3 | 5 | 7 | 9 | 11 | 13 |

我正在尝试创建一个可以动态转置两行的数据透视语句。

期望的输出:

|    Date    | Person | Values |
--------------------------------
| 01/01/2018 | 123 | 2 |
| 01/02/2018 | 123 | 4 |
| 01/03/2018 | 123 | 6 |
| 01/04/2018 | 123 | 8 |
| 01/05/2018 | 123 | 10 |
| 01/06/2018 | 123 | 12 |
| 01/15/2018 | 246 | 1 |
| 01/16/2018 | 246 | 3 |
| 01/17/2018 | 246 | 5 |
... and so on. Date order not important

以下查询将有助于初始化事物:

DECLARE @WeekTable TABLE (
[PeriodStart] datetime
, [Person] int
, [Day1] int
, [Day2] int
, [Day3] int
, [Day4] int
, [Day5] int
, [Day6] int
, [Day7] int
)

INSERT INTO @WeekTable(
[PeriodStart],[Person],[Day1],[Day2],[Day3],[Day4],[Day5],[Day6],[Day7]
)
VALUES ('01/01/2018','123','2','4','6','8','10','12','14')
,('01/15/2018','246','1','3','5','7','9','11','13')

最佳答案

其他选择是使用APPLY 运算符

SELECT DATEADD(DAY, Days-1, Dates) Date, a.Person, Value
FROM @WeekTable t CROSS APPLY (
VALUES (PeriodStart, Person, 1, Day1), (PeriodStart, Person, 2, Day2),
..., (PeriodStart, Person, 7, Day7)
)a(Dates, Person, Days, Value)

关于SQL 动态旋转 "Week"表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49163768/

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