gpt4 book ai didi

json - 对于 JSON 路径格式

转载 作者:行者123 更新时间:2023-12-04 20:56:54 26 4
gpt4 key购买 nike

背景:

我有一个 JSON nvarchar(max)名为“问题”的列,从单行看起来像这个真实的例子......

{"211":0,"212":0,"213":0,"214":0,"215":0,"216":0,"217":0,"218":0,"219":0,"220":"1","221":"1","222":"1","223":"1","224":"1","225":"1","226":"1","227":"1","228":"1","229":"1","230":"1","231":"1","232":"1"}

我目前正在为示例“调用”生成此示例 JSON 片段...
[
{
"call": {
"id": 200643,
"yes_answers": [
{
"question_id": "220"
},
{
"question_id": "221"
},
{
"question_id": "222"
},
{
"question_id": "223"
},
{
"question_id": "224"
},
{
"question_id": "225"
},
{
"question_id": "226"
},
{
"question_id": "227"
},
{
"question_id": "228"
},
{
"question_id": "229"
},
{
"question_id": "230"
},
{
"question_id": "231"
},
{
"question_id": "232"
}
]
}
}
]

.. 使用这个查询...
select c.call_id as [call.id],
(
select x.[key]
from [call].[triage_questions] tq
cross apply openjson(questions, '$') as x
where value = 1 and tq.call_id = c.call_id
for json path
) as [call.yes_answers]
from [call].[dimension] c
where call_id = 200643
for json path

我的问题:

我不喜欢格式化“yes_answers”数组的方式。我想要更像这样的东西:
[
{
"call": {
"id": 200643,
"yes_answers": [
220,
221,
222,
223,
224,
225,
226,
227,
228,
229,
230,
231,
232
]
}
}
]

这是有效的吗?或者我应该以不同的方式滚动它?还是离开它?

我将使用 SQL 将“yes_answers”数组中的每个 question_id 引用到引用表中,我正在寻找与该问题相关联的真/假标志。如果这很重要,JSON 此时不会离开 SQL。

编辑:

感谢 @Tomato32 , 我找到了 this other question我想,这帮助我足够接近。

我的查询现在看起来像这样......
select c.call_id as [call.id],
json_query(replace(replace((
select x.[key] as question_id
from [call].[triage_questions] tq
cross apply openjson(questions, '$') as x
where value = 1 and tq.call_id = c.call_id
order by x.[key]
for json path
), N'{"question_id":', N''), '"}', '"')) as [call.yes_answers]
from [call].[dimension] c
where call_id = 200643
for json path

我生成的 JSON 看起来像这样......
[
{
"call": {
"id": 200643,
"yes_answers": [
"220",
"221",
"222",
"223",
"224",
"225",
"226",
"227",
"228",
"229",
"230",
"231",
"232"
]
}
}
]

我无法去掉 "yes_answers"数组中 int 值周围的引号,但我认为这无关紧要,我不会浪费任何时间:) 谢谢大家!! !

最佳答案

我只更新了您的替换语句以去掉“[数字]”中的引号,如下所示:-

select c.call_id as [call.id],
json_query(replace(replace((
select x.[key] as question_id
from [call].[triage_questions] tq
cross apply openjson(questions, '$') as x
where value = 1 and tq.call_id = c.call_id
order by x.[key]
for json path
), N'{"question_id":"', N''), '"}', '')) as [call.yes_answers]
from [call].[dimension] c
where call_id = 200643
for json path

在我的测试中,输出如下:-
[{"call":{"id":200643,"yes_answers":[220,221,222,223,224,225,226,227,228,229,230,231,232]}}]

关于json - 对于 JSON 路径格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52747530/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com