quartz-scheduler - 如何使用 Quartz XML 插件声明一次性简单触发器？

Question

我正在尝试设置一个作业，使其在我的调度程序第一次启动时运行一次，然后在每天午夜运行一次。这是我的作业和触发器的 XML。一天一次触发有效，但一次性触发无效。

    <job>
      <name>MyJob</name>
      <group>MyJobGroup</group>
      <job-type>MyScheduledJob, MyJobAssembly</job-type>
      <description>My job, yo</description>
      <durable>true</durable>
      <recover>false</recover>
    </job>
    <trigger>
      <cron>
        <name>MyTrigger</name>
        <group>MyTriggerGroup</group>
        <job-name>MyJob</job-name>
        <job-group>MyJobGroup</job-group>
        <cron-expression>0 0 0 1/1 * ? *</cron-expression>
      </cron>
        <simple>
            <name>MyOneTimeTrigger</name>
            <group>MyTriggerGroup</group>
            <description>Run once at startup, G</description>
            <misfire-instruction>SmartPolicy</misfire-instruction>
            <volatile>false</volatile>
            <job-name>MyJob</job-name>
            <job-group>MyJobGroup</job-group>
            <repeat-count>0</repeat-count>
            <repeat-interval>0</repeat-interval> 
      </simple>
    </trigger>

Answer 1

通过不起作用我猜你的意思是触发器永远不会触发。也许是因为它没有延迟它会失火？添加<start-time-seconds-in-future/>怎么样？ future 一段时间？

<simple>
        <name>MyOneTimeTrigger</name>
        <group>MyTriggerGroup</group>
        <description>Run once at startup, G</description>
        <misfire-instruction>SmartPolicy</misfire-instruction>
        <volatile>false</volatile>
        <job-name>MyJob</job-name>
        <job-group>MyJobGroup</job-group>
        <start-time-seconds-in-future>60</start-time-seconds-in-future>
        <repeat-count>0</repeat-count>
        <repeat-interval>0</repeat-interval> 
</simple>

如果它对你有用，你必须知道一些你可能认为是错误或功能的东西:如果你重新启动服务器，因为触发器已经触发并被删除，它会再次触发。见: Quartz XML plugin reschedules fired triggers after restart .