sql - Oracle 中不同行中相同字段的日期/时间差异

Question

我有以下 View ，我需要做的是获取具有相同 Vehicle AND OrderCode 的每 2 条记录之间的字段 ActionDate 的日期差异，我如何在 Oracle 数据库中实现这一点。

还要考虑到减去的日期应该是具有 的日期。模式 O - 模式 I

我需要获取差异列表才能获得该时间的平均值。

谢谢你的帮助。

Answer 1

您可以使用分析 LAG() OVER() 函数来获取日期之间的差异。

例如，

SQL> WITH t AS
  2  (
  3    select 'O' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 16:34:35','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  4    union all
  5    select 'I' as "MODE", 'V1234567890' as  Vehicle, '1411196232' as OrderCode, to_date('2014-11-19 15:27:09','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  6    union all
  7    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 14:03:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
  8    union all
  9    select 'I' as "MODE", 'V2987654321' as  Vehicle, '1411206614' as OrderCode, to_date('2014-11-20 13:47:02','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 10    union all
 11    select 'O' as "MODE", 'V2987654321' as  Vehicle, '1411185798' as OrderCode, to_date('2014-11-20 01:40:58','yyyy-mm-dd hh24:mi:ss') as ActionDate from dual
 12    union all
 13    SELECT 'I' AS "MODE", 'V2987654321' AS  Vehicle, '1411185798' AS OrderCode, to_date('2014-11-20 00:47:02','yyyy-mm-dd hh24:mi:ss') AS ActionDate FROM dual
 14  )
 15  SELECT "MODE",
 16    Vehicle,
 17    OrderCode,
 18    TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
 19    TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
 20    ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
 21  FROM t;

M VEHICLE     ORDERCODE  DT                  LAG_DT                    DIFF
- ----------- ---------- ------------------- ------------------- ----------
I V1234567890 1411196232 2014-11-19 15:27:09
O V1234567890 1411196232 2014-11-19 16:34:35 2014-11-19 15:27:09 .046828704
I V2987654321 1411185798 2014-11-20 00:47:02
O V2987654321 1411185798 2014-11-20 01:40:58 2014-11-20 00:47:02 .037453704
I V2987654321 1411206614 2014-11-20 13:47:02
O V2987654321 1411206614 2014-11-20 14:03:02 2014-11-20 13:47:02 .011111111

6 rows selected.

SQL>

注意: WITH 子句 用于构建 示例数据 ，在您的实际情况下使用您的表，您需要使用 _104567920 _106 _106 _106 _106 _107

SELECT "MODE",
  Vehicle,
  OrderCode,
  TO_CHAR(ActionDate,'yyyy-mm-dd hh24:mi:ss') dt,
  TO_CHAR(LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate),'yyyy-mm-dd hh24:mi:ss') lag_dt,
  ActionDate - LAG(ActionDate) OVER(PARTITION BY Vehicle,OrderCode ORDER BY Vehicle, ActionDate) diff
FROM your_table;

我把 TO_CHAR 放在了演示目的，你想要的输出是 DIFF 列。关于 MODE ，您可以将其添加到过滤器谓词中。