jsp - 如何从 HttpServlet 请求中获取操作以分派(dispatch)到多个页面

Question

我正在使用页面 Controller 模式。如何通过检测请求操作然后根据结果进行调度来为两个不同的页面使用同一个 Controller ？

这是我的代码:

account.jsp

<form name="input" action="<%=request.getContextPath() %>/edit" method="get">
   <input type="submit" value="Modifier" />
</form>

帐户 Servlet

public void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        System.out.println("received HTTP GET");

        String action = request.getParameter("action");

        if (action == null)
        {
            // the account page
            dispatch(request, response, "/account");    
        }
        else if (action == "/edit") {
            // the popup edit page
            dispatch(request, response, "/edit");
        }

        protected void dispatch(HttpServletRequest request,
            HttpServletResponse response, String page)
            throws javax.servlet.ServletException, java.io.IOException {
        RequestDispatcher dispatcher = getServletContext()
            .getRequestDispatcher(page);
        dispatcher.forward(request, response);
}
    }

Answer 1

我发现使用 HttpServletRequest#getServletPath()得到我需要的东西，所以我不需要解析任何东西!

public void doGet(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {
    System.out.println("received HTTP GET");

    String action = request.getServletPath();

    if (action.equals("/account"))
    {
        // the account page
        dispatch(request, response, "/content/account.jsp");    
    }
    else if (action.equals("/edit")) 
    {
        // the popup edit page
        dispatch(request, response, "/content/edit.jsp");
    }
}

protected void dispatch(HttpServletRequest request,
    HttpServletResponse response, String page)
        throws javax.servlet.ServletException, java.io.IOException {
    RequestDispatcher dispatcher = getServletContext()
            .getRequestDispatcher(page);
    dispatcher.forward(request, response);
    }
}