excel - 如果连续值高于基线值，则更改图表标记颜色

Question

如果图表中的值由超过基线值 0.7 的 3 个连续尖峰组成，我目前正在创建一个 VBA 宏来更改图表标记的颜色。
例如，在下图中，我创建了一个宏，如果值高于基线值，则将所有标记颜色更改为红色，但如果有 3 个连续值高于基线值，则不会。

我的代码
这是我尝试过的 - 如果值超过 0.7，则将标记颜色更改为红色

Sub Tester()

Dim cht As Chart, s As Series, p As point
Dim vals, x As Integer

    Set cht = ThisWorkbook.Worksheets("mySheet3").ChartObjects("Chart 1").Chart
    Set s = cht.SeriesCollection(1)
    vals = s.Values
    
    For x = LBound(vals) To UBound(vals)
      If vals(x) > 0.7 Then
        With s.Points(x)
            .MarkerBackgroundColor = RGB(255, 0, 0)
            .MarkerForegroundColor = RGB(255, 0, 0)
        End With
      End If
    Next x
    
End Sub

Answer 1

为此，您需要使用窗口大小来检查总是连续检查 3 个点，如果它们高于基线，如果它们是着色的，并进一步移动 1 以检查连续的下 3 个点。

Option Explicit

Sub Tester()
    Dim cht As Chart
    Set cht = ThisWorkbook.Worksheets("mySheet3").ChartObjects("Chart 1").Chart
    
    Dim s As Series
    Set s = cht.SeriesCollection(1)
    
    Dim vals As Variant
    vals = s.Values
    
    Const WindowSize As Long = 3
    Dim Colorize As Boolean
    
    Dim x As Long
    For x = LBound(vals) To UBound(vals)
        If x + WindowSize - 1 <= UBound(vals) Then
            Colorize = True
            Dim w As Long
            For w = x To x + WindowSize - 1
                If Not vals(w) > 0.7 Then
                    Colorize = False
                    Exit For
                End If
            Next w
            If Colorize Then
                For w = x To x + WindowSize - 1
                    With s.Points(w)
                        .MarkerBackgroundColor = RGB(255, 0, 0)
                        .MarkerForegroundColor = RGB(255, 0, 0)
                    End With
                Next w
             End If
        End If
    Next x
End Sub