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hibernate - 示例标准 Hibernate Multiple Join/Table SQL

转载 作者:行者123 更新时间:2023-12-04 20:09:26 28 4
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我有这个 SQL 查询

select pr.*,p.id, cf.nome, p.valor_total as "valor total", f.descricao as "forma de pagamento", t.descricao as "tipo de pagamento", s.descricao as "Status" from pedido p
left join cliente c on c.id = p.id_cliente
left join cliente_pessoa_fisica cf on cf.id_cliente = c.id
left join forma_pagamento f on f.id = p.id_forma_pagamento
left join tipo_pagamento t on t.id = p.id_tipo_pagamento
left join status_pedido s on s.id = p.id_status_pedido
left join itempedido itp on itp.id_pedido = p.id
left join produto pr on pr.id = itp.id_produto

如何使用此查询创建 Criteria Hibernate SQL?

最佳答案

这是我最好的照片,类(class)名称可能不同

    CriteriaBuilder qb = entityMan.getCriteriaBuilder();
CriteriaQuery<Pedido> criteriaQuery = qb.createQuery(Pedido.class);
Root<Pedido> root = criteriaQuery.from(Pedido.class);

/**
* if the Cliente is a list you should use ListJoin instead of Join so it's ListJoin<Pedido, Cliente>
*if you don't have metadata you can use root.join(root.get("id_cliente")).
*/
Join<Pedido, Cliente> cliente = root.join(Pedido_.id_cliente, JoinType.LEFT);
Join<Cliente, ClientePessoaFisica> clientePessoaFisica = cliente.join(Cliente_.id, JoinType.LEFT);//or if you don't have metadata you can use root.join(cliente.get("id_cliente"))
Join<Pedido, FormaPagamento> formaPagamento = root.join(Pedido_.id_forma_pagamento, JoinType.LEFT); //or if you don't have metadata you can use root.join(root.get("id_forma_pagamento"))
Join<Pedido, TipoPagamento> tipoPagamento = root.join(Pedido_.id_tipo_pagamento, JoinType.LEFT);//or if you don't have metadata you can use root.join(root.get("id_tipo_pagamento"))
Join<Pedido, StatusPedido> statusPedido = root.join(Pedido_.id_status_pedido, JoinType.LEFT);//or if you don't have metadata you can use root.join(root.get("id_status_pedido"))
Join<Pedido, Itempedido> itempedido = root.join(Pedido_.id, JoinType.LEFT);//or if you don't have metadata you can use root.join(root.get("id"))
Join<Itempedido, Produto> produto = itempedido.join(Itempedido_.id_produto, JoinType.LEFT);//or if you don't have metadata you can use root.join(itempedido.get("id_produto"))

/**
* Here you can select what ever you want, here's an example and you can complete it yourself :)
* But I would remove this line and select the object itself Pedido
* Now it depends on you FetchType of the relationships, you might need fetch join
*/
criteriaQuery.multiselect(root.get("id"), root.get("valor_total"), formaPagamento.get("descricao"));

TypedQuery<Pedido> query = entityMan.createQuery(criteriaQuery);
return query.getResultList();

关于hibernate - 示例标准 Hibernate Multiple Join/Table SQL,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20544785/

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