svg - 如果我们知道角度，计算SVG线性渐变属性x1 y1 x2 y2？

Question

正如我们在 SVG 中所知，角度线性渐变是通过设置属性 x1,x2,y1,y2 来实现的。但是，如果我们只得到角度，

1.如何计算x1,y1,x2,y2的结果？

2. 这个公式是否正确 tan (angle ) = (y2-y1)/(x2-x1)？我如何计算所有参数。

Answer 1

基于 JT- 的答案，这里有一个函数可以完全满足您在 Javascript 中的需求。只需调用此函数，将元素和度数作为整数传递即可。我还添加了“左”、“右”、“上”、“下”作为可选参数。

function svg_linear_gradient_direction(element, direction){

    if(direction === "left"){

        element.setAttributeNS(null, "x1", "100%");
        element.setAttributeNS(null, "y1", "0%");
        element.setAttributeNS(null, "x2", "0%");
        element.setAttributeNS(null, "y2", "0%");

    } else if(direction === "right"){

        element.setAttributeNS(null, "x1", "0%");
        element.setAttributeNS(null, "y1", "0%");
        element.setAttributeNS(null, "x2", "100%");
        element.setAttributeNS(null, "y2", "0%");

    } else if(direction === "down"){

        element.setAttributeNS(null, "x1", "0%");
        element.setAttributeNS(null, "y1", "0%");
        element.setAttributeNS(null, "x2", "0%");
        element.setAttributeNS(null, "y2", "100%");

    } else if(direction === "up"){

        element.setAttributeNS(null, "x1", "0%");
        element.setAttributeNS(null, "y1", "100%");
        element.setAttributeNS(null, "x2", "0%");
        element.setAttributeNS(null, "y2", "0%");

    } else if(typeof direction === "number"){

        var pointOfAngle = function(a) {
            return {
                x:Math.cos(a),
                y:Math.sin(a)
            };
        }

        var degreesToRadians = function(d) {
            return ((d * Math.PI) / 180);
        }

        var eps = Math.pow(2, -52);
        var angle = (direction % 360);
        var startPoint = pointOfAngle(degreesToRadians(180 - angle));
        var endPoint = pointOfAngle(degreesToRadians(360 - angle));

        if(startPoint.x <= 0 || Math.abs(startPoint.x) <= eps)
            startPoint.x = 0;

        if(startPoint.y <= 0 || Math.abs(startPoint.y) <= eps)
            startPoint.y = 0;

        if(endPoint.x <= 0 || Math.abs(endPoint.x) <= eps)
            endPoint.x = 0;

        if(endPoint.y <= 0 || Math.abs(endPoint.y) <= eps)
            endPoint.y = 0;

        element.setAttributeNS(null, "x1", startPoint.x);
        element.setAttributeNS(null, "y1", startPoint.y);
        element.setAttributeNS(null, "x2", endPoint.x);
        element.setAttributeNS(null, "y2", endPoint.y);
    }
}