python - 如何在每第 n 次出现空格但重叠时拆分字符串

Question

我有一个字符串:

Your dog is running up the tree.

我希望能够在每个第 k 个空间上分割它但有重叠。例如，每隔一个空间:

Your dog is running up the tree.
out = ['Your dog', 'dog is', 'is running', 'running up', 'up the', 'the tree']

每隔一个空间:

Your dog is running up the tree.
out = ['Your dog is', 'dog is running', 'is running up', 'running up the', 'up the tree']

我知道我可以做类似的事情

>>> i=iter(s.split('-'))                  
>>> map("-".join,zip(i,i)) 

但这不适用于我想要的重叠。有任何想法吗？

Answer 1

我建议先在每个空格处拆分，然后在迭代列表时将所需数量的单词重新组合在一起

s = 'Your dog is running up the tree.'
lst = s.split()

def k_with_overlap(lst, k):
    return [' '.join(lst[i:i+k]) for i in range(len(lst) - k + 1)]

k_with_overlap(lst, 2)

['Your dog', 'dog is', 'is running', 'running up', 'up the', 'the tree.']