gnuplot - 使用 gnuplot，如何 'cut out' 使用图形的 y 轴区域

Question

我试图绘制一个图形，在 Y 轴上我有 CPU 利用率，当前范围是 0-100%。我的数据只包含 0-20% 和 80-100%，而我只有 20-80% 的大空白。有什么办法可以“剪掉”这个空白区域，让观众可以更详细地看到 0-20% 和 80-100% 范围内发生的事情？

谢谢你。

Answer 1

正如 Christoph 在评论中所说，这需要使用 set multiplot 手动完成。和删除边框等。一个例子:

set multiplot
# remove border and ytics from right hand side
set border 7
set ytics nomirror
# set top and bottom margins for both halves of the plot
set tmargin at screen 0.96
set bmargin at screen 0.1
# set left and right margins for left half of the plot
set lmargin at screen 0.1
set rmargin at screen 0.5
# set xrange for left half of the plot
set xrange [0:2*pi]
# set some lines to delimit transition from one half of the plot to next
set arrow from screen 0.50,0.08 to screen 0.52,0.12 nohead
set arrow from screen 0.49,0.08 to screen 0.51,0.12 nohead
set arrow from screen 0.50,0.94 to screen 0.52,0.98 nohead
set arrow from screen 0.49,0.94 to screen 0.51,0.98 nohead
# plot left half
plot sin(x) not
# remove border from left hand side and set ytics on the right
set border 13
unset ytics
set y2tics
set format y2 ""
# set left and right margins for right half of the plot
set lmargin at screen 0.51
set rmargin at screen 0.91
# set xrange for right half of the plot
set xrange [13.5:13.5+2*pi]
# plot
plot sin(x) axes x1y2