bash - awk 或其他命令如何获取字符串 curl 结果的变量值？

Question

在 bash 脚本中，我正在为获取数据的 POST 请求运行 curl

f_curl_get_data (){

read -p "start date : " start_date
read -p "end date : " end_date

# (!) NOTE 
# - the date time format must be YYYY-MM-DD

mng_type=users
user=myuser
secret=mysecret

curl --location --request POST 'https://myapi.com/api/v2.1/rest/exports' \
    --header 'Content-Type: application/json' \
    --header 'SDK-APP-ID: '$user'' \
    --header 'SDK-SECRET: '$secret'' \
    --data-raw '{
        "type":"'$mng_type'",
        "start_date":"'$start_date'",
        "end_date": "'$end_date'"
    }' 

}

我得到以下结果

{"results":{"created_at":"2020-03-13T07:04:14Z","download_url":"","error_message":"","original_filename":"2020-03-13T07:04:14Z_exported_users.json","percentage":0,"resource_name":"users","size":0,"status":"started","total_rows":0,"unique_id":"37c23e60-5b83-404a-bd1f-6733ef04463b"},"status":200}

如何使用 awk 命令或其他命令从变量“unique_id”中获取值？

37c23e60-5b83-404a-bd1f-6733ef04463b

感谢你

Answer 1

使用 sed

sed -e 's/.*unique_id":"\(.*\)\"}.*/\1/'

演示:

:>echo '{"results":{"created_at":"2020-03-13T07:04:14Z","download_url":"","error_message":"","original_filename":"2020-03-13T07:04:14Z_exported_users.json","percentage":0,"resource_name":"users","size":0,"status":"started","total_rows":0,"unique_id":"37c23e60-5b83-404a-bd1f-6733ef04463b"},"status":200}' | sed -e 's/.*unique_id":"\(.*\)\"}.*/\1/'
37c23e60-5b83-404a-bd1f-6733ef04463b