由于 tclError，使用 tkinter 的 python 程序无法运行

Question

我正在尝试学习如何使用 tkinter 制作 GUI conde 是相当基本的，但我收到以下错误:

Exception has occurred: TclError
no display name and no $DISPLAY environment variable
  File "/home/josh/Documents/VSC/python/SECOM/mainWindow.py", line 7, in __init__
    self.wind = Tk()
  File "/home/josh/Documents/VSC/python/SECOM/mainWindow.py", line 12, in <module>
    MW = mainWindow()

当我用谷歌搜索此类错误时，只有树莓派或远程服务器之类的答案。我只是使用ubuntu(20.04)并且有一个conda(4.8.3)venv和python(3.8)。我也在使用 VSC 并将 venv 作为 VSC 中的解释器。帮助:c MainWindow.py

from tkinter import ttk
from tkinter import *

class mainWindow:
    def __init__(self):
        self.title = "SECOM"
        self.wind = Tk()
        self.wind.title(self.title)


if __name__ == '__main__':
    MW = mainWindow()
    window.mainloop()

Answer 1

你在谈论很多 windows在您的代码中，但实际上没有多少是 window .其中一些根本不算什么。尝试这个。

import tkinter as tk


class Root(tk.Tk):
    def __init__(self, **kwargs):
        tk.Tk.__init__(self, **kwargs)

        #PUT YOUR APP HERE


if __name__ == '__main__':
    root = Root()
    root.title("SECOM")
    root.mainloop()

这是您的脚本的问题

from tkinter import ttk
#importing like this pollutes your namespace
from tkinter import *

class mainWindow:
    def __init__(self):
        #there is no reason to store a reference to the title
        self.title = "SECOM"
        #why are you burying your root in a class property
        self.wind = Tk()
        #this is why you don't need a reference to title
        self.wind.title(self.title)


if __name__ == '__main__':
    #sure
    MW = mainWindow()
    #window? window where? You buried this in MW.wind
    window.mainloop()