sql - 您试图在 ms access 中执行不包含指定表达式 'out_time' 作为聚合函数的查询

Question

我使用 Ms access 作为我的数据库，我正在使用以下查询来获取工作时间:

select 
        in_time,
        out_time,
        datediff("n",b.in_time,c.out_time) as work_time,
        log_date,
        emp_id 
from 
    (select 
        LogTime as in_time,
        SrNo,
        LogID as emp_id,
        LogDate as log_date 
    from LogTemp 
    where Type='IN' ) as b
left join
    (select 
        SrNo as out_id, 
        LogTime as out_time,
        LogID as out_emp_id,
        LogDate as out_log_date 
      from LogTemp 
     where Type = 'OUT'
     group by SrNo) as c
on (b.SrNo <> c.out_id
    and b.emp_id = c.out_emp_id
    and b.log_date = out_log_date ) 
where  
    c.out_id > b.SrNo and 
    [log_date] >= #8/20/2012# and 
    [log_date] <= #8/20/2012# and 
    emp_id = "8" 
group by b.SrNo; 

但是当我执行查询时，我收到以下错误:

"you tried to execute a query that does not include the specified expression 'out_time'
 as an aggregate function in ms access" error.

任何我犯错误的建议。

Answer 1

您有几个错误，以防您尝试执行 GROUP BY .首先检查MSDN for GROUP BY syntax, recommendations and samples .

基本上，如果您使用 GROUP BY，无需深入研究。 , SELECT 上的任何列不受聚合函数影响的子句 SUM , AVG等，应该出现在 GROUP BY 上条款。因此，在您的情况下，您应该添加:

LogTime as out_time,
LogID as out_emp_id,
LogDate as out_log_date

进入第二个子查询的 GROUP BY。并添加

 in_time,
 out_time,
 datediff("n",b.in_time,c.out_time) as work_time,
 log_date,
 emp_id 

上主 GROUP BY在末尾。

但是，正如在一条评论中已经指出的那样，也许您想要做的是 ORDER BY .然后应该就像更换 GROUP 一样简单来自 ORDER它应该工作。只要确定这是你想要的。