bash - netstat:解析(awk？)输出以返回 "Program name"而不是 "PID/Program name"

Question

Ubuntu 14.04
netstat -p在同一列中输出两个“PID/程序名称”。我只想要该列中的“程序名称”。最简单的方法是什么？

实际输出

root@neo4j1:~# netstat -tlp
Active Internet connections (only servers)
Proto Recv-Q Send-Q Local Address           Foreign Address         State       PID/Program name
tcp        0      0 *:ssh                   *:*                     LISTEN      1020/sshd
tcp6       0      0 [::]:ssh                [::]:*                  LISTEN      1020/sshd
tcp6       0      0 [::]:7473               [::]:*                  LISTEN      31380/java
tcp6       0      0 [::]:7474               [::]:*                  LISTEN      31380/java

所需输出

root@neo4j1:~# netstat -tlp
Active Internet connections (only servers)
Proto Recv-Q Send-Q Local Address           Foreign Address         State       Program name
tcp        0      0 *:ssh                   *:*                     LISTEN      sshd
tcp6       0      0 [::]:ssh                [::]:*                  LISTEN      sshd
tcp6       0      0 [::]:7473               [::]:*                  LISTEN      java
tcp6       0      0 [::]:7474               [::]:*                  LISTEN      java

Answer 1

尝试

netstat -tlp | sed 's,[0-9]\+/,,'