sql - 每个日期时间增量一秒的填充表

Question

我有一个包含几千行的 MyDatabase.MyTable.DateCol，我想用日期时间填充它。我希望每个日期都比前一个日期大 1 秒。我该怎么做？

Answer 1

示例表

CREATE Table DateTable 
(ID INT IDENTITY(1,1),Name NVARCHAR(300), Data Datetime)
GO

测试数据

INSERT INTO DateTable (Name)
VALUES ('John'),('Mark'),('Phil'),('Simon'),('Sam'),('Pete'),('Josh')
GO

查询

;WITH CTE
AS
(
SELECT *, rn = ROW_NUMBER() OVER (ORDER BY ID ASC)  FROM DateTable
)
UPDATE CTE
SET  Data = DATEADD(SECOND, CTE.rn, GETDATE())

结果集

SELECT * FROM DateTable

ID  Name    Data
1   John    2013-11-06 20:34:59.310
2   Mark    2013-11-06 20:35:00.310
3   Phil    2013-11-06 20:35:01.310
4   Simon   2013-11-06 20:35:02.310
5   Sam     2013-11-06 20:35:03.310
6   Pete    2013-11-06 20:35:04.310
7   Josh    2013-11-06 20:35:05.310