ubuntu - Bash 脚本从输出信息中获取/提取特定信息/单词

Question

命令nvcc --version输出以下内容:

nvcc: NVIDIA (R) Cuda compiler driver
Copyright (c) 2005-2019 NVIDIA Corporation
Built on Wed_Oct_23_21:14:42_PDT_2019
Cuda compilation tools, release 10.2, V10.2.89

我正在尝试获取 cuda 版本，在这种情况下为 10.2从第 4 行开始。
因此我尝试了以下方法:

cudaVersion="$(nvcc --version| grep 'Cuda compilation ')"
echo "$cudaVersion"

然而，这给了我整行作为输出。但是我只想将版本分配给 cudaVersion我相信这必须与 cut 一起使用，但是我无法得到它
提前致谢

Answer 1

使用您显示的示例，您能否尝试以下操作。用 GNU 编写和测试 grep .

nvcc --version | grep -oP '^Cuda compilation.*release \K[0-9]+\.[0-9]+'

解释:为上述添加详细说明。

nvcc --version |  ##Running  nvcc --version command and sending its output to grep command.
grep -oP          ##Using grep command using -P option for enabling PCRE ERE here.  
'^Cuda compilation.*release \K[0-9]+\.[0-9]+'
                  ##Checking if line starts Cuda compilation till release space.
                  ##\K will skip till matched value(since we don't want in output) dot and digits.

或与任何 awk :

nvcc --version | 
awk '
  /^Cuda compilation.*release / && match($0,/release [0-9]+\.[0-9]+/){
    print substr($0,RSTART+8,RLENGTH-8)
}
'

解释:为上述添加详细说明。

nvcc --version |      ##Running command nvcc --version sending output to awk here as input.
awk '                 ##starting awk program from here.
  /^Cuda compilation.*release / && match($0,/release [0-9]+\.[0-9]+/){
                      ##Checking condition if line starts from Cuda compilation till release AND using match function to release space digits dot digits here.
    print substr($0,RSTART+8,RLENGTH-8)  ##printing sub string with matches value and printing Only version here.
}
'