kotlin - 如何命名线程？

Question

我该如何命名这个线程？

    override val t: Thread = Thread {
        try {
            transmit()
        } catch (e: Exception) {
            println("Transmitter throws exception: $e")
        }
    }

Answer 1

您可以使用 stdlib 中的 thread 函数创建命名线程:

fun thread(
    start: Boolean = true, 
    isDaemon: Boolean = false, 
    contextClassLoader: ClassLoader? = null, 
    name: String? = null, 
    priority: Int = -1, 
    block: () -> Unit
): Thread

只需更改您的代码:

override val t: Thread = thread(name = "transmitter thread") {
        try {
            transmit()
        } catch (e: Exception) {
            println("Transmitter throws exception: $e")
        }
    }

为了从线程内部设置线程的名称，您不能使用接收 Runnable 的 Thread 的构造函数。您需要使用对象表达式对 Thread 类进行子类化:

val thread = object : Thread() {
  override fun run() {
       name = "thread with random name: ${Math.random()}"
  }
}