ssis - 可以在 SSIS 中实现运行总和，而无需任何手动编码吗？

Question

我有一个必须运行总计的场景，我可以通过纯 T-SQL 或脚本任务来实现这一点。但我想避免手动编码，并使用 ETL 工具功能。是否可能以及如何。

我有表余额

SELECT '00000001' AS [AccountNo], CONVERT(date,'20080828') AS [Date],10 AS [DailyMovement]
INTO   balances
UNION  ALL
SELECT '00000001' AS [AccountNo], CONVERT(date,'20080829') AS [Date],5 AS [DailyMovement]
UNION  ALL
SELECT '00000001' AS [AccountNo], CONVERT(date,'20080830') AS [Date],7 AS [DailyMovement]
UNION  ALL
SELECT '00000002' AS [AccountNo], CONVERT(date,'20080828') AS [Date],8 AS [DailyMovement]
UNION  ALL
SELECT '00000002' AS [AccountNo], CONVERT(date,'20080829') AS [Date],6 AS [DailyMovement]

我得到了这样的结果。

SELECT b1.[AccountNo]
,      b1.[Date]
,      b1.[DailyMovement]
,      SUM(b2.[DailyMovement]) AS [RunningTotal]
FROM   balances b1
INNER  JOIN balances b2 ON  b1.[AccountNo] = b2.[AccountNo]
                           AND b1.[Date] >= b2.[Date]
GROUP  BY b1.[AccountNo],b1.[Date],b1.[DailyMovement]; 

想在 SSIS 中执行此操作而无需手动编码

Answer 1

您是否尝试添加查询

SELECT b1.[AccountNo]
,      b1.[Date]
,      b1.[DailyMovement]
,      SUM(b2.[DailyMovement]) AS [RunningTotal]
FROM   balances b1
INNER  JOIN balances b2 ON  b1.[AccountNo] = b2.[AccountNo]
                           AND b1.[Date] >= b2.[Date]
GROUP  BY b1.[AccountNo],b1.[Date],b1.[DailyMovement]; 

到 oledbsource 以将其用作 Source，然后直接将其指向 oledbdestination？