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php - 网页标题用户名

转载 作者:行者123 更新时间:2023-12-04 18:19:14 25 4
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我想把登录用户的名字作为页面的标题。但我不知道该怎么做。我尝试了几种方法,但每种方法都显示解析错误。这是我用于登录用户然后显示他的详细信息的 php 代码。

<?php

//if the login session does not exist therefore meaning the user is not logged in
if(strcmp($_SESSION['uid'],"") == 0){
//display and error message
echo "<center>You need to be logged in to user this feature!</center>";
}else{
//otherwise continue the page

//this is out update script which should be used in each page to update the users online time
$time = date('U')+50;
$update = mysql_query("UPDATE `employer` SET `online` = '".$time."' WHERE `id` = '".$_SESSION['uid']."'");
$display_query = mysql_query("SELECT * FROM employer WHERE `id` = '".$_SESSION['uid']."'");
echo "<table id='pageTable'><tbody><th>Your Details</th>";
echo "<tbody>";
while($row = mysql_fetch_array($display_query)){
echo "<tr><td>Name&#58;&nbsp;</td><td>".$row['name']."</td><tr>";
$titlename = $row['name'];
echo "<tr><td>E&#45;Mail ID&#58;&nbsp;</td><td>".$row['email']."</td><tr>";
echo "<tr><td>Contact No&#46;&#58;&nbsp;</td><td>".$row['contact']."</td><tr>";
echo "<tr><td>Company&#58;&nbsp;</td><td>".$row['company']."</td><tr>";
echo "<tr><td>Designation&#58;&nbsp;</td><td>".$row['designation']."</td><tr>";
}

echo "</tbody>";
echo "</table>";
echo "<table><tr><td>";
echo '<div class="button"><a href="functions/logout.php">Logout</a></td></tr></table>';


//make sure you close the check if they are online
}

?>

最佳答案

您需要在输出 <head> 之前获取所需的数据页面的部分,然后包含 <title> 其中的元素。

<title><?php echo htmlspecialchars($myTitle); ?></title>

关于php - 网页标题用户名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11029357/

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