数据透视表中括号中的 SQL Server 2005 百分比

Question

这是来自 here 的后续问题.
我有一些输出并且能够添加一个总列，但现在我需要使用该列来添加这样的百分比:

| LESSONID     RESPONSE COUNT-> | 0       | 1       | 2       | 3       | 4       | N |
---------------------------------------------------------------------------------------                         
|lesson1                        | 1 (20%) | 1 (20%) | 1 (20%) | 1 (20%) | 1 (20%) | 5 |
|lesson2                        | 1 (20%) | 1 (20%) | 1 (20%) | 2 (40%) | 0       | 5 |
|lesson3                        | 1 (20%) | 1 (20%) | 0       | 3 (60%) | 0       | 5 |
|lesson4                        | 0       | 1 (20%) | 4 (80%) | 0       | 0       | 5 |
|lesson5                        | 0       | 5 (100%)| 0       | 0       | 0       | 5 |

我在这里找到了一些帮助，但无法将它们全部融合在一起。

Here is what I have so far

*我也在 SQL Server 2005 上，这在 SQLFiddle 中没有表示

Answer 1

您可以像处理任何其他查询一样格式化数据透视查询的结果。因此，您可以将百分比连接到其各自的来源。 Here is a SQL FIDDLE .

SELECT RC.lessonid AS 'lessonid     response count->'
  , convert (varchar(20), isnull([0], 0))
  + isnull (' ('
-- As both numbers are integers don't forget to cast one of them into double
-- If you dislike * 100 format or want more precise result.
  + convert (varchar(20), [0] * 100 / RCN.N)
  + '%)', '') as [0]
  , convert (varchar(20), isnull([1], 0))
  + isnull (' ('
  + convert (varchar(20), [1] * 100 / RCN.N)
  + '%)', '') as [1]
  , convert (varchar(20), isnull([2], 0))
  + isnull (' ('
  + convert (varchar(20), [2] * 100 / RCN.N)
  + '%)', '') as [2]
  , convert (varchar(20), isnull([3], 0))
  + isnull (' ('
  + convert (varchar(20), [3] * 100 / RCN.N)
  + '%)', '') as [3]
  , convert (varchar(20), isnull([4], 0))
  + isnull (' ('
  + convert (varchar(20), [4] * 100 / RCN.N)
  + '%)', '') as [4]
  ,RCN.N
FROM (
    SELECT lessonid
        ,response
        ,count(response) AS respcnt
    FROM tblRChoices
    GROUP BY lessonid
        ,response
    ) TableResponseCount
PIVOT(SUM(respcnt) FOR response IN (
            [0]
            ,[1]
            ,[2]
            ,[3]
            ,[4]
            )) RC
JOIN (SELECT lessonid, count(lessonid) as N FROM tblRChoices GROUP BY lessonid) RCN 
ON RC.lessonid = RCN.lessonid