sed 命令帮助总结类似的日志信息

Question

我正在尝试为一个应用程序制作一个日志文件摘要工具，该工具创建许多重复条目，只有一个不同的后缀来指示执行点。

这是一个通用版本:
包含这些内容的 text_file (infile_grocery.txt)。

milk skim fruit apple banana
milk skim fruit orange
milk skim fruit mango
milk skim fruit pomegranate
milk 2 percent fruit cherry tomato
milk 2 percent fruit peach
milk whole fruit pineapple
milk skim fruit strawberry raspberry
milk skim fruit strawberry rhubarb
milk whole fruit pineapple

我希望得到的是:

milk skim fruit apple banana, orange, mango, pomegranate
milk 2 percent fruit cherry tomato, peach
milk whole fruit pineapple
milk skim fruit strawberry raspberry, strawberry rhubarb
milk whole fruit pineapple

我目前编写的命令行是:

sed -rn "{H;x;s|^(.+) fruit ([^\n]+)\n(.*)\1 fruit (.+)$|\1 fruit \2, \4|;x}; ${x;s/^\n//;p}" infile_grocery.txt

但我得到的结果是:

milk skim fruit apple banana, mango, strawberry raspberry
milk skim fruit strawberry rhubarb
milk whole fruit pineapple

我以某种方式丢弃输入。任何有更好想法的大师如何构建这个？

Answer 1

这是 awk解决方案。

awk -F fruit '
$1==x{
    printf ",%s", $2
    next
}
{
    x=$1
    printf "\n%s", $0
}
END {
    print ""
}' input.txt 

输出

milk skim fruit apple banana, orange, mango, pomegranate
milk 2 percent fruit cherry tomato, peach
milk whole fruit pineapple
milk skim fruit strawberry raspberry, strawberry rhubarb
milk whole fruit pineapple