validation - 如何在 Perl 6 中定义 Int 的 Arrayreference 的自定义类型？

Question

如何在 Perl 6 中定义 Int 数组引用的自定义类型？我试过这个，但它不起作用:

subset Array_of_Int of Array where *.all ~~ Int;

my $n = My::Class.new( option => < 22 3 4 5 > );

# Type check failed in assignment to $!option; expected My::Class::Array_of_Int but got List in block <unit> at ...

Answer 1

在我的::类中:

has Int @.option;