Scalactic Accumulation 的 withGood of Seq

Question

如何在 Seq[Or] 上使用 withGood 累加 Scalactic 的 Or？

所以我有类似下面的代码:

val cs: Seq[BigDecimal Or ErrorMessage]

所以当 cs 中的所有值都像这样 Good 时我需要做一些事情

Accumulation.withGood(cs){...}

感谢任何帮助

Answer 1

或者，根据 http://www.scalactic.org/user_guide/OrAndEvery :

object worksheet {
  println("Welcome to the Scala worksheet")   //> Welcome to the Scala worksheet

  import org.scalactic._
  import Accumulation._

  val test1: Seq[Or[Long, Every[ErrorMessage]]] = Seq(
      Good(1L),
      Good(2L),
      Bad(One("An error")),
      Good(4L),
      Bad(One("Another error"))
      )                                       //> test1  : Seq[org.scalactic.Or[Long,org.scalactic.Every[org.scalactic.ErrorMe
                                              //| ssage]]] = List(Good(1), Good(2), Bad(One(An error)), Good(4), Bad(One(Anoth
                                              //| er error)))
  val test2: Seq[Or[Long, Every[ErrorMessage]]] = Seq(
      Good(1L),
      Good(2L),
      Good(3L),
      Good(4L),
      Good(5L)
      )                                       //> test2  : Seq[org.scalactic.Or[Long,org.scalactic.Every[org.scalactic.ErrorMe
                                              //| ssage]]] = List(Good(1), Good(2), Good(3), Good(4), Good(5))

  test1.combined                              //> res0: org.scalactic.Or[Seq[Long],org.scalactic.Every[org.scalactic.ErrorMess
                                              //| age]] = Bad(Many(An error, Another error))

  test2.combined                              //> res1: org.scalactic.Or[Seq[Long],org.scalactic.Every[org.scalactic.ErrorMess
                                              //| age]] = Good(List(1, 2, 3, 4, 5))
}