java - 有没有办法检查是否使用 WebDriver (java) 重新加载了元素？

Question

我需要在每次更新后验证一个元素。例如:Lowrtemperature:7.54 一段时间后值更改为 Lowrtemperature:3.79，然后这里的其他值每次都在一段时间后(时间变化)更改。但我需要驱动程序在更改后获取更新的值。如何使用 selenium webdriver 获取元素，这里页面没有重新加载，只有元素值被重新加载

public boolean waitForTextToChange(WebElement element, String currentText) {
                return !element.getText().equals(currentText);
            }


public String Lowertemperature_14_L(){
    WebElement element = driver.findElement(By.xpath(".//*[@id='webForm:sensorContainer']/div[@class='tile tile23 show-all hide-tiny']/div[@class='meteo-line1']/div[1]/div[@class='icon']/div[@class='icon-label0']"));
   String currentText = element.getText();
   WebDriverWait wait = new WebDriverWait(driver, 10);
   wait.until(waitForTextToChange(element, currentText));
   return currentText;
   }

Answer 1

//这里的第一个值将是 ex.4.56，然后在 20 秒后该值更新为 3.67，然后在每 20 秒的跨度后依此类推(时间在 8、10、6 之后的某个时间有所变化，依此类推) .我使用 wait.until(Expectedconditions.stalenessOf(element)) 检查值是否更新，然后我们从 ui 获取新的更新值并在更新值之前和之后进行验证

 wait = new WebDriverWait(driver, 20);
                By container = By.xpath(".//*[@id='webForm:sensorContainer']/div/div[1]/div[1]/div/div[6]");
                wait.until(ExpectedConditions.visibilityOfElementLocated(container));

                /* Read the text that appears in the XPath text control. */
                WebElement ajaxControl = driver.findElement(container);
                String ajaxTextFirstPara = ajaxControl.getText().trim();

                WebElement ele= driver.findElement(container);
                try{
                       wait.until(ExpectedConditions.stalenessOf(ele));
                }catch(TimeoutException e){
                }

                /* Wait for the new content to appear in the xpath text control. */
                By newAjaxcontrol =  container;
                Wait<WebDriver> newwait = new FluentWait<>(driver)
                        .withTimeout(60, TimeUnit.SECONDS)
                        .pollingEvery(5, TimeUnit.SECONDS)
                        .ignoring(NoSuchElementException.class);
                newwait.until(ExpectedConditions
                        .visibilityOfElementLocated(newAjaxcontrol));
                WebElement undergroundTemperature_14_L_value= driver.findElement(newAjaxcontrol);
                String undergroundTemperature_14_L =undergroundTemperature_14_L_value.getText().trim();
                if(ajaxTextFirstPara!= undergroundTemperature_14_L)
                {
                    System.out.println("diffeerent");
                }else{
                    System.out.println("same");
                }