scheme - 如何在Racket中将实数转换为精确整数？

Question

如何将20.2格式的值转换为(random ...)接受的值？

我已经尝试过这些:

;; x defined by some earlier maths and of form 20.2

(random (round x))
(random (floor x))

但是两者都返回:

random: contract violation
expected: (or/c (integer-in 1 4294967087) pseudo-random-generator?)
given: 20.0

Answer 1

这些也有效，根据documentation，它们只是您使用方法的简写:

(random (exact-round x))
(random (exact-floor x))