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json - 使用 jq reduce 汇总多个值

转载 作者:行者123 更新时间:2023-12-04 17:43:17 25 4
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如何使用jq的reduce函数来处理多次操作?

给定一个模型:

{
"usage" : {
"os:linux" : {
"2018_11_18" : {
"amount" : 601046342,
"credits" : 99783
},
"2018_10_18" : {
"amount" : 839785106,
"credits" : 173121
}
}
}
}

和JQ文件:

reduce .usage."os:linux"[] as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits
)

我得到:

{
"credits": 272904,
"minutes": 0
}

很酷,但我想兼顾这两个领域,例如:

reduce .usage."os:linux"[] as $item (
{"credits":0,"minutes":0};
."credits" += $item.credits,
."minutes" += $item.amount /1000/60
)

分号导致错误,逗号通过,但只处理最后一个任务,i,e,

{
"credits": 0,
"minutes": 24013.85746666667
}

最佳答案

总有明确的方式:

reduce .usage."os:linux"[] as $item (
{"credits": 0, "minutes": 0 };
{
"credits": (.credits + $item.credits),
"minutes": (.minutes + $item.amount / 60000)
}
)

关于json - 使用 jq reduce 汇总多个值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53420046/

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