python-3.x - 为什么不能在 cx_Freeze 中创建线程池？

Question

Traceback (most recent call last):

  File "C:\Users\Jun\AppData\Local\Programs\Python\Python35\lib\site-packages\cx_Freeze\initscripts\__startup__.py", line 14, in run

    module.run()

  File "C:\Users\Jun\AppData\Local\Programs\Python\Python35\lib\site-packages\cx_Freeze\initscripts\Console.py", line 26, in run

    exec(code, m.__dict__)

  File "D:/ruanjian/new/Ui-Design/hand_up_625.py", line 25, in <module>

    from keras.models import load_model

  File "C:\Users\Jun\AppData\Local\Programs\Python\Python35\lib\site-packages\keras\__init__.py", line 3, in <module>

    from . import utils

  File "C:\Users\Jun\AppData\Local\Programs\Python\Python35\lib\site-packages\keras\utils\__init__.py", line 4, in <module>

    from . import data_utils

  File "C:\Users\Jun\AppData\Local\Programs\Python\Python35\lib\site-packages\keras\utils\data_utils.py", line 19, in <module>

    from multiprocessing.pool import ThreadPool

ImportError: No module named 'multiprocessing.pool'

Answer 1

尝试将'multiprocessing' 添加到setup.py 脚本中build_exe_options 的packages 列表:

build_exe_options = {"packages": ['multiprocessing']}

# ...

setup(  name = ...,  # complete!
        ...
        options = {"build_exe": build_exe_options},
        executables = [Executable(...)])

参见 cx_Freeze documentation了解更多详情。

另请注意，您必须为卡住的脚本调用 multiprocessing.freeze_support() 才能继续使用多处理。根据documentation :

Add support for when a program which uses multiprocessing has been frozen to produce a Windows executable. (Has been tested with py2exe, PyInstaller and cx_Freeze.)

One needs to call this function straight after the if __name__ == '__main__' line of the main module. For example:

from multiprocessing import Process, freeze_support

def f():
    print('hello world!')

if __name__ == '__main__':
    freeze_support()
    Process(target=f).start()

If the freeze_support() line is omitted then trying to run the frozen executable will raise RuntimeError.

Calling freeze_support() has no effect when invoked on any operating system other than Windows. In addition, if the module is being run normally by the Python interpreter on Windows (the program has not been frozen), then freeze_support() has no effect.