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reactjs - 像 'useLocation' 这样的 react 路由器钩子(Hook)的 stub 不起作用

转载 作者:行者123 更新时间:2023-12-04 17:31:01 34 4
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我正在尝试为具有路由器 Hook 的 React 功能组件编写单元测试 useLocation()像下面。

//index.js
function MyComponent(props) {
const useQuery = () => new URLSearchParams(useLocation().search);
const status = useQuery().get('status');

if (status === 'success') {
return <ShowStatus message="OK" secret={props.secret} />;
} else {
return <ShowStatus message="NOT OK" secret={props.secret} />;
}
}

//index.spec.js
describe('Test MyComponent', () => {
it('should send OK when success', () => {
sinon.stub(reactRouter, 'useLocation').returns({
search: {
status: 'success'
}
});
const props = { secret: 'SECRET_KEY' };
const wrapper = enzyme.shallow(<MyComponent.WrappedComponent {...props}/>);

expect(wrapper.type()).to.have.length(MyComponent);
expect(wrapper.props().message).to.equal('OK');
expect(wrapper.props().secret).to.equal(props.secret);
});

it('should send NOT OK when error', () => {
sinon.stub(reactRouter, 'useLocation').returns({
search: {
status: 'error'
}
});
const props = { secret: 'SECRET_KEY' };
const wrapper = enzyme.shallow(<MyComponent.WrappedComponent {...props}/>);

expect(wrapper.type()).to.have.length(MyComponent);
expect(wrapper.props().message).to.equal('NOT OK);
expect(wrapper.props().secret).to.equal(props.secret);
});
});
连我都 stub useLocation我收到错误
TypeError: Cannot read property 'location' of undefined
at useLocation (node_modules\react-router\modules\hooks.js:28:10)
我正在尝试测试 ShowStatus组件根据查询参数使用正确的 Prop 呈现。
任何建议/帮助表示赞赏。
更新:
我注意到即使我是从 react-router-dom 进口的在生产和测试代码中。我正在看到一个来自 react-router 的产品.

最佳答案

使用 MemoryRouter组件包装你的组件比 stub 更好 useLocation钩。

keeps the history of your “URL” in memory (does not read or write to the address bar). Useful in tests and non-browser environments like React Native.


我们可以通过 initialEntries 为您测试的组件提供“URL” Prop 。 index.tsx :
import React from 'react';
import { useLocation } from 'react-router-dom';

export function ShowStatus({ message, secret }) {
return <div>{message}</div>;
}

export function MyComponent(props) {
const useQuery = () => new URLSearchParams(useLocation().search);
const status = useQuery().get('status');

if (status === 'success') {
return <ShowStatus message="OK" secret={props.secret} />;
} else {
return <ShowStatus message="NOT OK" secret={props.secret} />;
}
}
index.test.tsx :
import { mount } from 'enzyme';
import React from 'react';
import { MemoryRouter } from 'react-router';
import { MyComponent, ShowStatus } from './';

describe('MyComponent', () => {
it('should send OK when success', () => {
const props = { secret: 'SECRET_KEY' };
const wrapper = mount(
<MemoryRouter initialEntries={[{ search: '?status=success' }]}>
<MyComponent {...props} />
</MemoryRouter>
);
expect(wrapper.find(ShowStatus).props().message).toEqual('OK');
expect(wrapper.find(MyComponent).props().secret).toEqual(props.secret);
});

it('should send NOT OK when error', () => {
const props = { secret: 'SECRET_KEY' };
const wrapper = mount(
<MemoryRouter initialEntries={[{ search: '?status=error' }]}>
<MyComponent {...props} />
</MemoryRouter>
);

expect(wrapper.find(ShowStatus).props().message).toEqual('NOT OK');
expect(wrapper.find(MyComponent).props().secret).toEqual(props.secret);
});
});
测试结果:
 PASS  examples/59829930/index.test.tsx (8.239 s)
MyComponent
✓ should send OK when success (55 ms)
✓ should send NOT OK when error (8 ms)

-----------|---------|----------|---------|---------|-------------------
File | % Stmts | % Branch | % Funcs | % Lines | Uncovered Line #s
-----------|---------|----------|---------|---------|-------------------
All files | 100 | 100 | 100 | 100 |
index.tsx | 100 | 100 | 100 | 100 |
-----------|---------|----------|---------|---------|-------------------
Test Suites: 1 passed, 1 total
Tests: 2 passed, 2 total
Snapshots: 0 total
Time: 9.003 s
包版本:
"enzyme": "^3.11.0",
"enzyme-adapter-react-16": "^1.15.5",
"jest": "^26.6.3",
"react": "^16.14.0",
"react-router-dom": "^5.2.0",

关于reactjs - 像 'useLocation' 这样的 react 路由器钩子(Hook)的 stub 不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59829930/

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